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julia-pushkina [17]
3 years ago
13

There is a line whose slope is 1/6 and whose y-intercept is 4. what is its equation in slope intetecept form?

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0
Your equation will be y = 1/6x + 4

this is in slope-intercept form which is y = mx + b

m is the slop and b is the y-intercept
Stolb23 [73]3 years ago
6 0
Answer:
y = \frac{1}{6} x + 4

Explanation:
The equation of the lone has a general formula:
y = mx + c
where:
m is the slope of the line = 1/6
c is the y-intercept = 4

Substitute with the givens in the above formula to get the equation as follows:
y = mx + c
y = \frac{1}{6} x + 4

Hope this helps :)
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Write an equation for the statement: A kilogram is equal to approximately 2.2 pounds. A cinder block weighs x pounds. A brick ha
navik [9.2K]

the total mass in kilograms y of the cinder block and brick is  y=0.45x + 0.6 .

<u>Step-by-step explanation:</u>

Here we have , A kilogram is equal to approximately 2.2 pounds. A cinder block weighs x pounds. A brick has a mass of 0.6 kilogram. We need to find What is the total mass in kilograms y of the cinder block and brick . Let's find out :

According to given data in question ,

⇒ 1kg = 2.2pounds

⇒ 1(pounds) = \frac{1}{2.2}kg

A cinder block weighs x pounds and a brick has a mass of 0.6 kilogram . Let total mass in kg of the cinder block and brick is y , i.e.

⇒ y (kg)= x (pounds) + 0.6 kg

⇒ y (kg)= x (\frac{1}{2.2}kg) + 0.6 kg

⇒ y=0.45x + 0.6

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Wholemark is an internet order business that sells one popular New Year greeting card once a year. The cost of the paper on the
erma4kov [3.2K]

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

                                = $0.05 + $0.15

                                = $0.20

Compute the total demand as follows:

Total demand = Mean × n

                       = 2000 × 4

                       = 8000

Compute the standard deviation of total demand as follows:

SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

         = $2.15 - $0.20

         = $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}

                               =\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907

Use Excel's NORMSINV{0.907} function to find the Z-score.

<em>z</em> = 1.322

Compute the optimal production quantity for the card as follows:

\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\

                                               =8000+(1.322\times 1000)\\=8000+1322\\=9322

Thus, the optimal production quantity is 9,322 cards.

8 0
3 years ago
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