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podryga [215]
3 years ago
15

Y

Chemistry
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

TIX. y) -> (5x 271

Explanation:

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Determine the number of carbon atoms in 1.00 kg of carbon dioxide.
olga2289 [7]

Answer:

1.37x10²⁵atoms of carbon

2.74x10²⁵ atoms of oxygen.

33.7g of KNO₃

Explanation:

To answer this question you must use molar mass of carbon dioxide (44g/mol) and 1 mole are 6.022x10²³atoms.

1.00kg are 1000g of CO₂. Moles are:

1000g CO₂ * (1mol / 44g) = 22.73 moles of CO₂ = 22.73 moles of carbon.

In atoms:

22.73 moles C * (6.022x10²³atoms / 1mole) = 1.37x10²⁵atoms of carbon

There are 22.73 moles of CO₂ * 2 = 45.45 moles of oxygen are present in the carbon dioxide. In atoms:

45.45 moles Oxygen * (6.022x10²³atoms / 1mole) = 2.74x10²⁵ atoms of oxygen.

1 mole of Potassium nitrate, KNO₃, contains 3 moles of oxygen. 1 mol of oxygen are:

1.00 mol O * (1mol KNO₃ / 3 moles O) = 0.33 moles of KNO₃

As molar mass of KNO₃ is 101.1g/mol:

0.33 moles of KNO₃ * (101.1g / mol) = 33.7g of KNO₃

5 0
3 years ago
Read 2 more answers
Help!
GarryVolchara [31]

I'm pretty certain the answer is 2) because fluorine is a diatomic gas meaning it travels with 2 molecules (simplified). It is a gas so molecules should also be spread out so the answer cannot be 3) or 4).

Hope this helps! :)

8 0
3 years ago
Three friends were kicking soccer balls at a neighborhood field. Three soccer balls were rolling across the field. The black soc
BARSIC [14]

Answer: d :The blue and orange soccer balls; they have more mass than the black soccer ball, but changed speed by the same amount.

3 0
3 years ago
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How would you convert 500cc of 2M H2so4 in g/l and normality?​
Ann [662]

Concentration :

196 g/L and 4 N

<h3> </h3><h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

500 cc of 2M H₂SO₄

V = 500 cc = 0.5 L

mol H₂SO₄

\tt mol=M\times V=2\times 0.5=1

mass H₂SO₄ (MW = 98 g/mol)

\tt mass=mol\times MW=1\times 98=98~g

concentration in g/L :

\tt \dfrac{98}{0.5}=196~g/L

concentration in normality

Relationship between normality and molarity

N = M x n (n=valence , amount of H⁺ or OH⁻)

so :

\tt N=2\times 2(n=2~for~H_2SO_4\rightarrow 2H^+)\\\\N=4

6 0
3 years ago
Based on the solubility chart, which of the listed salts is the most soluble at 25 degrees Celsius?
VashaNatasha [74]
I think it's Potassium iodide because it has the highest solubility at 25°C.
4 0
4 years ago
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