Answer:
D) D =
, E) (C, D) = (
Explanation:
Part D) two expressions are indicated
3C + 4D = 5
2C +5 D = 2
let's simplify each expression
3C + 4D = 5
4D = 5 - 3C
we divide by 4
D =
The other expression
2C +5 D = 2
2C = 2 - 5D
C =
we can see that the correct result is 1
Part E.
It is asked to solve the problem by the substitution method, we already have
D =
we substitute in the other equation
2C +5 D = 2
2C +5 (5/4 - ¾ C) = 2
we solve
C (2 - 15/4) + 25/4 = 2
-7 / 4 C = 2 - 25/4
-7 / 4 C = -17/4
7C = 17
C =
now we calculate D
D =
D = 5/4 - 51/28
D =
D = - 16/28
D =
the result is (C, D) = (
)
Answer:
The atoms ,molecules, or compound present at the start of a chemical reaction that parcitipate in the reaction are <u><em>the reactants.</em></u>
Explanation:
The chemical reaction is the way in which one substance reacts against another. So, a chemical reaction consists of the transformation of some substances into others, that is, the process of arranging atoms and bonds when chemical substances come into contact.
In a chemical reaction, the initial substances are called reactants, while the new substances obtained are called products.
So, <u><em>the atoms ,molecules, or compound present at the start of a chemical reaction that parcitipate in the reaction are the reactants.</em></u>
Answer:
The time taken is 
Explanation:
From the question we are told that
The speed of first car is 
The speed of second car is 
The initial distance of separation is 
The distance covered by first car is mathematically represented as

Here
is the initial distance which is 0 m/s
and
is the final distance covered which is evaluated as
So


The distance covered by second car is mathematically represented as

Here
is the initial distance which is 119 m
and
is the final distance covered which is evaluated as

Given that the two car are now in the same position we have that

