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erastova [34]
4 years ago
10

Consider four sealed, rigid containers with the following volumes: 50 mL, 100 mL, 250 mL, and 500 mL. If each of these contains

.25 moles of helium gas at standard temperature, which container would have the greatest pressure?
Chemistry
1 answer:
dsp734 years ago
5 0
First, we assume that helium behaves as an ideal gas such that the ideal gas law is applicable.
                                     PV = nRT
where P is pressure, V is volume, n is number of moles, R is universal gas constant, and T is temperature. From the equation, if n, R, and T are constant, there is an inverse relationship between P and V. From the given choices, the container with the greatest pressure would be the 50 mL. 
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Which elements have similar behavior? barium silicon aluminum strontium osmium beryllium
victus00 [196]

Answer:

Barium, strontium and beryllium, all belong to the group 2. Silicon belong to group 14. Aluminium belong to group 13 and Osmium belong to group 8. Hence, the elements which have similar behavior are Barium, strontium and beryllium.

Explanation:

hope this helps

6 0
3 years ago
Explain why a mole is a special number?
RoseWind [281]
A mole is a unit used to convert between the number of atoms and grams in an element. The information given on the periodic table is based on a mole or 6.02 *10^23 atoms of the element.
3 0
4 years ago
Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph
meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

  • <em>Volume of the acid, V = 250 mL</em>
  • <em>pH of the acid, = 2.4</em>

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398

The molarity of the nitric acid is calculated as follows;

=  0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M

The number of moles of the nitric acid is calculated as follows;

moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.

The molar mass of nitric acid is calculated as;

HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol

The mass of the nitric acid contained in the calculated number of moles is calculated as;

mass = moles\  \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

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2 years ago
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Answer:

i laughed at a dead body lowkey

Explanation:.

3 0
3 years ago
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