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prohojiy [21]
4 years ago
14

Number of moles in 3.70 x 10^-1 g of boron

Chemistry
2 answers:
aleksley [76]4 years ago
8 0
The answer is 10.81 g of boron.
elena55 [62]4 years ago
8 0

Answer:

0.0342 mol

Explanation:

The molar mass of boron is 10.81 g/mol, that is, 1 mole of boron (6.02 × 10²³ molecules of boron) has a mass of 10.81 grams. This is the ratio that we will use to find the number of moles in 3.70 × 10⁻¹ g, using a conversion fraction.

3.70 × 10⁻¹ g B × (1 mol B / 10.81 g B) = 0.0342 mol B

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Answer: \Delta H^{0}=-173.72 kJ/mol

Explanation: <u>Enthalpy</u> <u>Change</u> is the amount of energy in a reaction - absorption or release - at a constant pressure. So, <u>Standard</u> <u>Enthalpy</u> <u>of</u> <u>Formation</u> is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}

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Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: \Delta H^{0}= -1002.82 kJ/mol

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Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H]

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So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

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