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3 years ago

Factor this for me please!

Mathematics

1 answer:

Igoryamba3 years ago

8 0

$-28x^2y^4+36xy^4+40y^4=-4y^4(7x^2-9x-10)=-4y^4(7x^2-14x+5x-10)\\\\-4y^4\left[(7x(x-2)+5(x-2)\right]=-4y^4(x-2)(7x+5)$

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Which ordered pair makes both inequalities true? y < 3x – 1 y > –x + 4 On a coordinate plane, 2 straight lines are shown.

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Answer:

(4,0)

Step-by-step explanation:

we have

$y< 3x-1$ ----> inequality A

$y \geq -x+4$ ----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

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case 2) (1,2)

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case 3) (0,4)

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case 4) (2,1)

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Inequality B

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