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tekilochka [14]
3 years ago
13

What mass of water is formed when 16g of hydrogen react with excess oxygen​

Chemistry
2 answers:
artcher [175]3 years ago
8 0

Hello!

To start off, we must look at atomic masses. Atoms all have different weights, so we must first find hydrogen and oxygen's atomic masses.

Oxygen: 16.00 amu

Hydrogen: 1.01 amu

Now, moving on to the weight of water itself. Water has the formula of H20, with two hydrogen atoms and one oxygen. Therefore, <u>add up the amus to get the weight of one molecule of water.</u>

1.01 + 1.01 + 16.00 = 18.02 amu

Now, to see the ratio of each component. Since hydrogen weighs a total of 2.02 amu (1.01 + 1.01) in the entire atom, we can state that hydrogen makes up about 0.112 of the weight of water. Now apply that ratio to 16 g, and solve.

0.112x = 16

142.857143 = x

So therefore, about 143 grams of water are made when 16g of hydrogen reacts with excess oxygen.

Hope this helps!

Norma-Jean [14]3 years ago
6 0

Answer:

144 grams of water is formed when 16 grams of hydrogen gas react with excess oxygen gas.

Explanation:

2H_2+O_2\rightarrow 2H_2O

Moles of hydrogen gas = \frac{16 g}{2 g/mol}=8 mol

According to reaction, 2 moles of hydrogen gas gives 2 moles of water.

Then 8 moles of hydrogen gas will give;

\frac{2}{2}\times 8mol=8 mol of water

Mass of 8 mole sof water ;

8 mol\times 18 g/mol= 144 g

144 grams of water is formed when 16 grams of hydrogen gas react with excess oxygen gas.

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