Well, to find out how many times 20.4 can split into 3.4, you need to divide 20.4÷3.4 and you will get 6, and Katrin (K-A-T-R-I-N) is 6 letters, so you have enough room, the answer is yes.
Answer:
give a picture
Step-by-step explanation:
Answer: a= c+11
Step-by-step explanation:
a has 9 more than b which has 2less than c
Answer: There are approximately 853827 new cases in 6 years.
Step-by-step explanation:
Since we have given that
Initial population = 570000
Rate at which population decreases is given by
![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Now,
First year =570000
Second year is given by
![570000\times (\frac{1}{3})](https://tex.z-dn.net/?f=570000%5Ctimes%20%28%5Cfrac%7B1%7D%7B3%7D%29)
Third year is given by
![570000(\frac{1}{3})^2](https://tex.z-dn.net/?f=570000%28%5Cfrac%7B1%7D%7B3%7D%29%5E2)
so, there is common ratio ,
it becomes geometric progression, as there is exponential decline.
so,
![570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6](https://tex.z-dn.net/?f=570000%2C570000%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%2C570000%5Ctimes%28%20%5Cfrac%7B1%7D%7B3%7D%29%5E2%2C......%2C570000%5Ctimes%20%28%5Cfrac%7B1%7D%7B3%7D%29%5E6)
a=570000
common ratio is given by
![r=\frac{a_2}{a_1}=\frac{1}{3}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Ba_2%7D%7Ba_1%7D%3D%5Cfrac%7B1%7D%7B3%7D)
number of terms = 6
Sum of terms will be given by
![S_n=\frac{a(1-r^n)}{(1-r)}](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Ba%281-r%5En%29%7D%7B%281-r%29%7D)
We'll put this value in this formula,
![S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16](https://tex.z-dn.net/?f=S_6%3D%5Cfrac%7B570000%281-%28%5Cfrac%7B1%7D%7B3%7D%29%5E6%7D%7B%281-%5Cfrac%7B1%7D%7B3%7D%29%7D%5C%5C%5C%5C%3D853827.16)
So, there are approximately 853827 new cases in 6 years.
Answer : The fifth term in the sequence is -2.
Step-by-step explanation :
As we are given that the expression to calculate the
term.
The expression is as follows:
![a_n=2(-1)^n](https://tex.z-dn.net/?f=a_n%3D2%28-1%29%5En)
where,
n is the number of term
Given:
n = 5
Now putting the value of n in the above expression, we get:
![a_n=2(-1)^n](https://tex.z-dn.net/?f=a_n%3D2%28-1%29%5En)
![a_5=2(-1)^5](https://tex.z-dn.net/?f=a_5%3D2%28-1%29%5E5)
![a_5=2\times (-1)](https://tex.z-dn.net/?f=a_5%3D2%5Ctimes%20%28-1%29)
![a_5=-2](https://tex.z-dn.net/?f=a_5%3D-2)
Therefore, the fifth term in the sequence is -2.