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Shtirlitz [24]
3 years ago
5

Why do chemists use the Lewis symbols to represent chlorine and sodium rather than drawing the electron diagrams of each element

before and after the reaction? A) Lewis symbols are easier to use. B) Lewis symbols are more scientific. C) Lewis symbols are more accurate. D) Lewis symbols are more abstract.
Chemistry
1 answer:
Debora [2.8K]3 years ago
3 0

Answer:

A

Explanation:

The answer is A, when you drawing the electron diagrams for each element you should draw all the electron for given element.

In the example of sodium and chlorine:

Sodium : 1s2, 2s2 2p6, 3s1

Chlorine: 1s2, 2s2, 2p6, 3s2 3p5

All the electron on the 1 and 2 levels will not be used to this representation because they will not leave the valence band. Only the electrons in the 3 level will interact in this example.

Remember that the sodium will lose an electron and become an cation. This happens because all the element will look for a stable form with the last band having 8 electron.

The chlorine will receive an electron, so the last band will have 8 electron.

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How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess
Anestetic [448]

Answer:

3.62moles

Explanation:

First let us generate a balanced equation for the reaction

2Na + Cl2 —> 2NaCl

Molar Mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the balanced equation = 2 x 58.5 = 117g

From the question,

46g of Na produced 117g of NaCl.

Therefore, 83g of Na will produce = (83 x 117)/46 = 211.11g of NaCl

Converting this mass (211.11g of NaCl) to mole, we obtain:

n = Mass /Molar Mass

n = 211.11/ 58.5

3.62moles

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3 years ago
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Citrus2011 [14]

Answer: homogeneous

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3 years ago
At a given temperature the vapor pressures of hexane and octane are 183 mmhg and 59.2 mmhg, respectively. Calculate the total va
Bas_tet [7]

Total vapor pressure can be calculated using partial vapor pressures and mole fraction as follows:

P=X_{A}P_{A}+X_{B}P_{B}

Here, X_{A} is mole fraction of A, X_{B} is mole fraction of B, P_{A} is partial pressure of A and P_{B} is partial pressure of B.

The mole fraction of A and B are related to each other as follows:

X_{A}+X_{B}=1

In this problem, A is hexane and B is octane, mole fraction of hexane is given 0.580 thus, mole fraction of octane can be calculated as follows:

X_{octane}=1-X_{hexane}=1-0.58=0.42

Partial pressure of hexane and octane is given 183 mmHg and 59.2 mmHg respectively.

Now, vapor pressure can be calculated as follows:

P=X_{hexane}P_{hexane}+X_{octane}P_{octane}

Putting the values,

P=(0.580)(183 mmHg)+(0.420)(59.2 mmHg)=131 mmHg

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Answer:

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