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timurjin [86]
3 years ago
10

2. Is this chemical equation balanced? 2C4H10 (g) + 13O2 (g) = 8CO2 (g) → 10H2O (l)

Physics
1 answer:
ehidna [41]3 years ago
3 0
Yes that is a balaned equation
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What are four types of pathogens and what type of disease or sickness do they cause?
Zanzabum

Bacteria( cholera)

Virus( AIDS)

Fungi(athlete's foot)

Protist( malaria)

Pleasssssssse mark me as brainliest

7 0
3 years ago
A liquid of density 830 kg/m3 flows through a horizontal pipe that has a cross-sectional area of 1.20 x 10-2 m2 in region A and
kicyunya [14]

Answer:

A) volume flow rate = 0.047 m3/s

B) mass flow rate = 39.01 kg/s

Explanation:

Detailed explanation and calculation is shown in the image below

3 0
3 years ago
Volume equals 4÷3 times pi times nine to the power of 3
Tcecarenko [31]

Answer:

V=972π

The equation I used... V=4/3π(9)^3

4 0
2 years ago
Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.88 × 1014 Hz. The speed of li
Nezavi [6.7K]

Answer: 430 nm.

Explanation:

The relation of wavelength and frequency is:

Formula used : \nu=\frac{c}{\lambda}

where,

\nu = frequency =6.88\times 10^{14}Hz

\lambda = wavelength  = ?

c = speed of light = 3.00\times 10^{8}m/s

Now put all the given values in this formula, we get

6.88\times 10^{14}=\frac{3.00\times 10^{8}m/s}{\lambda}

\lambda=\frac{3.00\times 10^{8}m/s}{6.88\times 10^{14}}=0.43\times 10^{-6}m=430m        (1nm=10^{-9}m)

Thus the wavelength (in nm) of the blue light emitted by a mercury lamp is 430 nm.

6 0
3 years ago
Calculate the average induced voltage between the tips of the wings of an airplane flying above East Lansing at a speed of 885 k
Yakvenalex [24]

Answer:

=0.855V

Explanation:

The induced voltage can be calculated using below expression

E =B x dA/dt

Where dA/dt = area

B= magnetic field = 6.90×10-5 T.

We were given speed of 885 km/h but we will need to convert to m/s for consistency of unit

speed = 885 km/h

speed = 885 x 10^3 m/hr

speed = 885 x 10^3/60 x60 m/s

speed = 245.8 m/s

If The aircraft wing sweep out" an area

at t= 50.4seconds then we have;

dA/dt = 50.4 x 245.8

= 123388.32m^2/s

Then from the expression above

E =B x dA/dt substitute the values of each parameters, we have

E = 6.90 x 10^-5 x 12388.32 V

E =0.855V

Hence, the average induced voltage between the tips of the wings is =0.855V

6 0
2 years ago
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