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2 years ago

I NEED HELP ASAP

Physics

1 answer:

erastovalidia [21]2 years ago

3 0

Answer:

Let the weight of the worker represented by X newton there is a normal force exerted at a distance of 0.67 cm

Explanation:

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A racquet ball with mass m = 0.221 kg is moving toward the wall at v = 13.9 m/s and at an angle of θ = 25° with respect to the h

Salsk061 [2.6K]

Answer:

1) 3.07kgm/s

2) 5.56kgm/s

3) 76.16N

4) 4.33kgm/s

5) 0.57s

6) -8.66J

Explanation:

Given

m = 0.221kg

v = 13.9m/s

θ = 25°

t = 0.073s

1) to get the magnitude of the initial momentum is the racquet ball. We use the formula,

P(i) = mv(i)

P(i) = 0.221 * 13.9

P(i) = 3.07kgm/s

2) Magnitude of the change in momentum of the ball,

P(i,x) = P(i) cos θ

P(i,x) = 3.07 * cos25

P(i,x) = 3.07 * 0.9063

P(i,x) = 2.78

ΔP = 2P(i,x)

ΔP = 2 * 2.78 = 5.56kgm/s

3) magnitude of the average force exerted by the wall,

F(ave) = ΔP/Δt

F(ave) = 5.56/0.073

F(ave) = 76.16N

4) ΔP(z) = mv(f) - mv(i)

ΔP(z) = 0.221*-7.8 - 0.221*11.8

ΔP(z) = -1.72 - 2.61

ΔP(z) = 4.33kgm/s

5) F(ave) = ΔP/Δt

Δt = ΔP/F(ave)

Δt = 4.33 / 76.16

Δt = 0.57s

6) KE(i) = 0.5mv(i)²

KE(f) = 0.5mv(f)²

ΔKE = 0.5m[v(f)² - v(i)²]

ΔKE = 0.5 * 0.221 [(-7.8)² - 11.8²]

ΔKE = 0.1105 ( 60.84 - 139.24 )

ΔKE = 0.1105 * -78.4

ΔKE = -8.66J

6 0

3 years ago

Ali is whirling a 2.0 kg bunch of bananas in a circular path having a radius of 0.50 m. The bananas complete 2 revolutions every

skad [1K]

Answer:

1) 2.467 N

2) a) 0.248m

b) 2.3π rad/sec

Explanation:

Given data:

mass of Banana bunch ( m ) = 2.0 kg

radius of circular path ( R ) = 0.5 m

number of revolutions completed = 2

Time to complete 2 revolutions = 6 seconds

1) Determine the force to keep the motion constant for one complete revolution in every 4 seconds

F = mv^2 / r ----- ( 1 )

where V = 2πR/T

where : R = 0.5 , m = 2, T = 4 seconds

Insert values into equation 1

F = 2 * 4π^2 * 0.5/4^2

= 2.467 N

2a) Calculate the maximum distance of coin from center

angular velocity ( w ) = v/r

coefficient of static friction ( μ ) = 0.25

$F_{c} = u mg$ ---- ( 1 )

mv^2/r = μmg --- ( 2 ) cancelling the mass on both sides eqn 2 becomes

v^2 = μ*g*r

dividing both sides of equation by r^2

w^2 = μ*g/r

hence determine distance ( r ) of coin from center

r = 0.25 * 9.81 / π^2 = 0.248 m

2b ) determine the maximum speed of rotation of the turntable for the coin to move relative to the turntable without slipping

distance coin is placed ( r ) = 4.7 cm = 0.047 m

find speed of rotation ( w )

w^2 = μ*g/r

w = √ 0.25 * 9.81/ 0.047

= 7.2236 rad/secs ≈ 2.3π rad/sec

3 0

2 years ago

Which part of fitness will help you hit a baseball farther?

Dmitry [639]

Answer:

Flexibility! :)

Explanation:

Agility: The ability to rapidly and accurately change the direction of the body. It is important in sports such as tennis which requires players to change direction quickly to hit the ball.

Flexibility: The muscles’ ability to move a joint through a full range of motion, and staying flexible is important to health and performance. As the body ages, the muscles, tendons, and ligaments stiffen, lose elasticity, and become less flexible.

Power: The ability to move the body parts swiftly while applying the maximum force of the muscles.

Body Composition: The combination of fat mass and fat-free mass, including bones, muscles, organs, and water.

6 0

2 years ago

Read 2 more answers

Anne lifts a 9.0 kg barbell with an upward force of 120 N. What is the magnitude of the acceleration of the barbell while Anne i

melamori03 [73]

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$