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Crazy boy [7]
3 years ago
13

Four engineers propose designs for door locks that are triggered by a sample of

Physics
1 answer:
sveta [45]3 years ago
7 0

Question:

A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will

trigger a photosensor (a device that senses forms of light) that will open the lock."

B. Engineer B: "When the sample alpha decays, it only releases large amounts of heat.

This will trigger a thermometer that will open the lock."

C. Engineer C: "When the sample alpha decays, it will lose mass, This will trigger a scale

that will open the lock."

D. Engineer D: "When the sample alpha decays, it will give off negatively charged alpha

particles. Because alpha particles are electrons, they will complete a circuit that will

open the lock."

Answer:

The correct option is;

A. Engineer A: "When the sample alpha decays, it will give off alpha particles. These will trigger a photosensor ( a device that senses forms of light) that will open the lock"

Explanation:

Here, we note that in alpha decay (α-decay) there is an emission of an alpha particle or helium nucleus with the transformation of the parent element nucleus into that of a different element, having reduced mass and atomic numbers

Alpha particles are a form of ionizing radiation with a mass of 6.64 × 10⁻²⁷ kg and therefore they can be sensed by a photo sensor but will be slowly sensed by a scale.

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Answer:

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2 years ago
Behavioral Adaptations: Behavior that animals begin life with that helps them meet their needs is called ________.
Arturiano [62]
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6 0
3 years ago
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A 600kg car is moving at 5 m/s to the right and elastically collided with a stationary 900 kg car. What is the velocity of the 9
11111nata11111 [884]

Answer:

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

m_{1} v_{1}=m_{2} v_{2}

\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }

\mathrm{v}_{1} \text { velocity before the collision }

\mathrm{v}_{2} \text { velocity after the collision }

\mathrm{m}_{1}=600 \mathrm{kg}

\mathrm{m}_{2}=900 \mathrm{kg}

\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}

600 \times 5=900 \times v_{2}

3000=900 \times v_{2}

\mathrm{v}_{2}=\frac{3000}{900}

\mathrm{v}_{2}=3.3 \mathrm{m} / \mathrm{s}

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

5 0
3 years ago
Two bicyclist, originally separated by a distance of 20 miles, are each traveling at a uniform speed of 10 miles per hour toward
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Answer:

D = 25 miles

Explanation:

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Since both bicyclists collide, we know that Xa=Xb, so:

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10*t = 20 - 10*t      Solving for t:

t = 1 hour  Now we can calculate the distance for the bee:

D = Vbee * t = 25 * 1 = 25 miles

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3 years ago
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vazorg [7]

frequency is equal to number of oscillations or vibrations upon time

therefore,

check picture

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