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Amiraneli [1.4K]

4 years ago

15

Як визначити амфотерний, луг чи основний елемент в хімії. Коли назви даєш, то пишеш наприклад CuSO4 - амф, купрум сульфат. Чому

саме купрум чи луг чи основний елемент. Поясніть будь ласка мені

1 answer:

Leno4ka [110]4 years ago

7 0

What? Please write in Spanish or English

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A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d

seraphim [82]

Answer:

The formula of the original halide is SrCl₂.

Explanation:

The balanced equation of this reaction is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X is the halide.

From the equation stichiometry, 1.0 mole of strontium halide will result in 1.0 mole of SrSO₄.

The number of moles of SrSO₄ <em>(n = mass/molar mass) </em>= (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.

The number of moles of SrX are 4.11 x 10⁻³ moles from the stichiometry of the balanced equation.

n = mass / molar mass, n = 4.11 x 10⁻³ moles and mass = 0.652 g.

The molar mass of SrX₂ = mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.

The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).

The atomic mass of halide X = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2 g/mole = 35.5 g/mole.

This is the atomic mass of Cl.

<em>So, the formula of the original halide is SrCl₂</em>.

4 0

4 years ago

What is the molarity of HCl if 34.81 mL of a solution of HCl contain 0.3297 g of HCl?

Temka [501]

Answer:

0.2598 M

Explanation:

Molarity is mol/L, so we have to convert the grams to moles and the mL to L. To convert between grams and moles you need the molar mass of the compound, which is 36.46g/mol.

$0.3297gHCl*\frac{1molHCl}{36.46gHCL} = 0.00904279 mol HCl$

$34.81 mLHCl * \frac{1L}{1000L} = 0.03481 L HCl$

$\frac{0.00904279molHCl}{0.03481 L HCl} = 0.25977554 mol/L$

Round to the lowest number of significant figures = 0.2598 M

6 0

4 years ago

neonofarm [45]

Answer:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Explanation:

Hello there!

In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:

$Cl_2+NaI\rightarrow I_2+NaCl$

It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Best regards!

8 0

3 years ago

A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is

Brilliant_brown [7]

But what is the width of the molecule

5 0

3 years ago

Scientific explanations

Sergio039 [100]

I think that it's cannot include supernatural explanations, or C.

If i got it wrong sorry

6 0

4 years ago