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Ksenya-84 [330]
3 years ago
7

0.007 decigrams = ? micrograms

Chemistry
1 answer:
bezimeni [28]3 years ago
7 0

0.007 - ?micrograms

0.007= 700micrograms

multiply the mass value by 100000

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HELP ASAP!! DUE TOMORROW!! WILL MARK AS BRAINLIEST IF ANSWERED IN THE NEXT HOUR!!
fgiga [73]
2. Left to right (smallest to largest) F-, Mg2+, Na+, and K+

5. Cs, Ga, As, N, O

6. Cs or H (probably cesium)

7. In or In 2+ (not sure which)

Hope this helps, I've never really seen questions like this before.
3 0
4 years ago
Assume that 25 ml of 0.440M NaCl are added to 25 ml of 0.320M AgNO3.
Genrish500 [490]
The balanced chemical equation would be as follows:

<span>NaCl + AgNO3 -> NaNO3 + AgCl

We are given the amounts of the reactants. We need to determine first which one is the limiting reactant. We do as follows:

0.0440 mol/L NaCl (.025 L) = 0.0011 mol NaCl -----> consumed completely and therefore the limiting reactant
0.320 mol/L AgNO3 (0.025 L) = 0.008 mol AgNO3

0.0011 mol NaCl ( 1 mol AgCl / 1 mol NaCl) = 0.0011 AgCl precipitate produced


</span>
8 0
3 years ago
Write any two uses of fractinal distillation​
lubasha [3.4K]

Answer:

Fractional distillation is used for the purification of water as well as separating acetone and water.

Fractional distillation is used in several industries like oil refineries and chemical plants mainly for purification and separation of many organic compounds.

6 0
3 years ago
Convert 7.1x10^25 molecules of water to moles
ruslelena [56]

Answer:

<h2>117.94 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.1 \times  {10}^{25} }{6.02 \times  {10}^{23} }  \\  = 117.940199...

We have the final answer as

<h3>117.94 moles</h3>

Hope this helps you

8 0
3 years ago
Calculate the molecular mass of HCL
liubo4ka [24]
Molecular mass of HCl :

H = 1.00794
Cl= 35.453

HCl :
 
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hope this helps!
8 0
4 years ago
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