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kati45 [8]
4 years ago
6

The reaction between aluminum and copper nitrate is a (A. Combustion, B. Decomposition. C. Double displacement D. Single Displac

ement E. Synthesis) reaction. The reaction produces aluminum nitrate because aluminum is (A. Equal in reactivity to, B. Less reactive than, C. More reactive than) copper.
Chemistry
1 answer:
salantis [7]4 years ago
5 0

Answer:

D. Single Displacement

C. More reactive than

Explanation:

Al + CuSO₄  --->  Cu + Al₂(SO₄)₃

The aluminum replaces the copper in the compound, isolating copper. This occurs because the aluminum is more reactive than the copper.

I hope this helps! :)

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How do I solve this?
Xelga [282]

Answer:

Explanation:

When you divide exponentials, you subtract the powers. For the numbers infront, just use a basic calculator for.

7.95/6.02 = 1.32

10^22/10^23 = 10^-1

1.32 x 10^-1 is your answer

7 0
3 years ago
An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0
Vlad [161]

Answer:

1.2 atm

Explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
  • Pressure of ethylene gas in the tank (P₁): ?
  • Volume of the gas in the torch (V₂): 300 L
  • Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm

3 0
3 years ago
How many grams of magnesium nitride is required to produce 25.00 g of magnesium hydroxide?
Lesechka [4]

Answer:

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

Explanation:

The balanced equation is

Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3

Molecular weight of magnesium nitride = 100.9494 g/mol

Molecular weight of magnesium hydroxide = 58.3197 g/mol

one mole of Mg3N2 produces three moles of 3Mg(OH)2

100.9494 g/mol of  Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2

1 gram of Mg3N2 produces

\frac{3* 58.3197}{100.9494 } \\1.733grams of Mg(OH)2

Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

6 0
3 years ago
If Magnesium Sulfide reacts with oxygen in the air, what will be produced?
sweet [91]

IF  magnesium sulfide reacts  with  oxygen in the air  it will  produce

 magnesium oxide  +  sulfur (IV) oxide

<u><em>explanation</em></u>

magnesium  sulfide burn in  oxygen  to produce magnesium  oxide  and sulfur (iv) oxide  according to the equation below

2MgS +3O2 →2MgO +2SO2

that is  2 moles of MgS  react with  3 moles of O2  to produce 2 moles of MgO   and  2 moles of SO2

6 0
3 years ago
When a 0.245-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.260-g sample
sveticcg [70]

Answer:

The heat of combustion per moles of caffeine is 4220 kJ/mol

Explanation:

Step 1: Data given

⇒ When  benzoic acid sample of 0.245 grams is burned the temperature rise is 1.643 °C

⇒ When 0.260 gram of caffeine is burned, the temperature rise is 1.436 °C

⇒ Heat of combustion of benzoic acid = 26.38 kJ/g

<u>Step 2:</u> Calculate the heat released: for combustion of benzoic acid

0.245 g benzoic acid *  26.38 kJ/g = 6.4631 kJ

<u>Step 3</u>: Calculate the heat capacity of the calorimeter:

c = Q/ΔT

Q = 6.4631 kJ   / 1.643°C = 3.934 kJ/ °C

<u>Step 4:</u> Calculate moles of a 0.260 g sample of caffeine:

Moles caffeine = Mass caffeine / Molar mass caffeine

0.260 grams/ 194.19 g/mol  = 0.0013389 moles

Step 5: Calculate heat released: for combustion of caffeine

Q = c * ΔT

Q = 3.934 kJ/°C * 1.436 °C = 5.65 kJ

Step 6: Calculate the heat of combustion per mole of caffeine  

5.65 kJ  /  0.0013389 moles = 4219.9 kJ/mol  ≈ 4220 kJ/mol

The heat of combustion per moles of caffeine is 4220 kJ/mol

4 0
4 years ago
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