Add up the molar mass of Mercury Oxide, and then divide the molar mass of Oxygen by the molar mass of the compound.
So...
mm of Hg + mm of O= 200.59g + 16g= 217g
16g/217g = .0737... x 100 = 7.37%
The correct answer here is B - when chlorine accepts an electron to
complete its octet and becomes a chlorion ion it becomes an Anion. An
anion is a negatively charged ion. Chloride ions are an important
electrolyte within the body.
5.512 litres is the volume of 15.2 grams of sulphur dioxide gas at STP.
Explanation:
Data given:
mass of sulphur dioxide = 15.2 grams
conditions is at STP whech means volume = 22.4 litres
atomic mass of sulphur dioxide = 64.06 grams/mole
Number of moles is calculated as:
number of moles = 
Putting the values in the equation:
number of moles = 
= 0.23 moles
Assuming that sulphur dioxide behaves as an ideal gas, we can calculate the volume as:
When 1 mole of sulphur dioxide occupies 22.4 litres at STP
Then 0.23 moles of sulphur dioxide occupies 22.4 x 0.23
= 5.152 litres is the volume.
The simple formula is C = n/V
n = mols
C = Concentration or Molarity
V = Volume in Liters.
n = 2
V = 4
C = 2 / 4
C = 0.5 mol/Litre