Answer:
1387.2g of Al2O3
Explanation:
The number of moles of aluminum oxide required to give the actual yield is obtained from the given mass of aluminum produced by the reaction. The percentage yield is used to obtain the theoretical yield of the aluminum. The number of moles produced theoretically can be used to calculate the amount of aluminum oxide required in moles and when we multiply the value obtained by the molar mass of aluminum oxide, we obtain the mass of aluminum oxide required.
C) 10 grams
Explanation:
Potassium chlorate (KCIO₃) have a solubility in water at 70 °C of 30 grams in 100 grams of water.
If our solution have already 20 grams of potassium chlorate salt dissolved that means we need another 10 grams of potassium chlorate to reach the saturation point.
Learn more:
Potassium chlorate solubility in water
brainly.com/question/10140327
I’m pretty sure it’s 760 mmHG (mm of mercury)
Explanation:
It is more difficult to remove electrons from the second shell or energy level because of the imbalance between the positive nuclear charge and the remaining electrons.
- The amount of energy required to remove electrons in ground state of an atom is the ionization energy.
- The first ionization energy is the energy needed to remove the most loosely bound electron of an atom in the gas phase in ground state.
- The second energy has a greater nuclear pull as it is closer to the nucleus.
- Both potassium and silicon have the same number of energy levels.