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4 years ago

A roller coaster car has a mass of 290. kilograms. Starting from rest, the car acquires

1 answer:

6 0

<span>The answer is 8.8 m/s^2. The acceleration (a) is the change in velocity (v) in time (t): a=Δv/t. Δv=v2-v1. Since the car starts from the rest, v1=0 m/s. The final velocity (v2) can be calculated from kinetic energy (KE) and the mass (m) of the car since KE=1/2*m*v2^2. From here: v2^2=2KE/m. v2=√(2KE/m). KE=3.13×10^5 J=3.13×10^5 kg*m^2/s^2, m=290 kg. v2=√(2*3.13×10^5 kg*m^2/s^2/290 kg)=√(2,158.62 m^2/s^2)=46.5 m/s. So, Δv=v2-v1=46.5 m/s - 0 m/s= 46.5 m/s. Now, we have Δv = 46.5 m/s and t=5.3 s, so the acceleration is: a=Δv/t=46.5 m/s/5.3 s = 8.8 m/s^2.</span>

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Air in human lungs has a temperature of 37.0°C and a saturation vapor density of 44.0 g/m³.

ioda

Answer:

(a). The maximum loss of water vapor by the person is $8.8\times10^{-2}\ g$

(b). The partial pressure of water vapor is $6.29\times10^{3}\ N/m^2$

Explanation:

Given that,

Temperature = 37.0°C

Volume of air = 2.00 L

Density of vapor = 44.0 g/m³

We need to calculate the maximum loss of water vapor by the person

Using formula of density

$m=\rho_{air}\times V_{air}$

Put the value into the formula

$m=44.0\times2.00\times10^{-3}$

$m=0.088\ g$

$m=8.8\times10^{-2}\ g$

(b). We need to calculate the partial pressure of water vapor

Using formula of pressure

$PV=nRT$

$P=\dfrac{nRT}{V}$

$P=\dfrac{\rho\times R\times T}{M}$

Put the value into the formula

$P=\dfrac{44\times8.314\times(37+273)}{18.01528}$

$P=6294.82\ N/m^2$

$P=6.29\times10^{3}\ N/m^2$

Hence, (a). The maximum loss of water vapor by the person is $8.8\times10^{-2}\ g$

(b). The partial pressure of water vapor is $6.29\times10^{3}\ N/m^2$

3 0

4 years ago

aliya0001 [1]

In Medicine, "etiology" means the origin or cause of a disease.

Similar to Hippocrates, modern scientists who study etiology believe that diseases come from natural causes such as bites from infected insects.

7 0

4 years ago

Satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to orbit at an

Volgvan

Answer:

0.63

Explanation:

We are given that

Radius of earth, $R_E=6370 km$

Radius of orbit A, $R_A=7590+6370=13960 km$

Radius of orbit B, $R_B=6370+15800=22170 km$

We have to find the ratio of the potential energy of satellite B to that of satellite A in orbit.

Potential energy of orbit A= $U_A=-\frac{GM}{R_A}=-\frac{GM}{13960}$

Potential energy of orbit B= $U_B=-\frac{GM}{R_B}=-\frac{GM}{22170}$

$\frac{U_B}{U_A}=\frac{13960}{22170}=0.63$

Hence,the ratio of the potential energy of satellite B to that of satellite A in orbit=0.63

8 0

4 years ago

Technician A says that valve overlap is the number of crankshaft degrees that both valves are closed. Technician B says that val

Vadim26 [7]

Answer: Technician B

Explanation: A valve overlap occurs when both the exhaust valve and the inlet valve are open at the same time.

It is also seen as the number of degrees at which both the inlet and exhaust valves are open.

Valve overlap helps in boosting the efficiency of the engine by taking advantage of the expelled pressure from the exhaust.

It is expressed mathematically in degrees of shaft rotation.

So, Technician B is very correct.

3 0

4 years ago

Give two examples of Newton's second law of motion

romanna [79]

<span>Examples of Newton's 2nd Law  If you use the same force to push a truck and push a car, the car will have more acceleration than the truck, because the car has less mass.  It is easier to push an empty shopping cart than a full one, because the full shopping cart has more mass than the empty one.</span>
from slide share.com

5 0

3 years ago

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