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2 years ago

What are the assumptions on which the cosmological principle is based?.

1 answer:

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Homogeneity and isotropy, On large enough scales, the Universe looks pretty much the same in all directions. The big bang theory is based on two assumptions: the first is centered around Einstein's general theory of relativity, which accurately describes gravity and the interactions of matter; and the second, also known as the cosmological principle, asserts that the universe is homogeneous and isotropic on a large enough scale.

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Balanced forces acting on an object cause the object to accelerate. Please select the best answer from the choices provided T F

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Balanced forces mean that there is no net force acting on the object. therefore, the object will not accelerate.

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A concave mirror with a radius of curvature of 20 cm has a focal length of

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Answer:

A concave mirror has a radius of curvature of 20 cm. What is it's focal length? If an object is placed 15 cm in front of it, where would the image be formed? What is it's magnification?

The focal length is of 10 cm, object distance is 30 cm and magnification is -2.

Explanation:

Given:

A concave mirror:

Radius of curvature of the mirror, as C = 20 cm

Object distance in-front of the mirror = 15 cm

Focal length:

Focal length is half of the radius of curvature.

Focal length of the mirror = $\frac{C}{2}$ = 10 cm

According to the sign convention we will put the mirror on (0,0) point, of the Cartesian coordinate open towards the negative x-axis.

Object and the focal length are also on the negative x-axis where focal length and image distance will be negative numerically.

We have to find the object distance:

Formula to be use:

⇒ $\frac{1}{focal\ length}= \frac{1}{image\ distance} + \frac{1}{object\ distance}$

⇒ Plugging the values.

⇒ $\frac{1}{-10} =\frac{1}{image\ distance}+\frac{1}{-15}$

⇒ $\frac{1}{-10} -\frac{1}{-15}=\frac{1}{image\ distance}$

⇒ $\frac{1}{-10} + \frac{1}{15}=\frac{1}{image\ distance}$

⇒ $\frac{-3+2}{30} =\frac{1}{image\ distance}$

⇒ $\frac{-1}{30} =\frac{1}{image\ distance}$

⇒ $-30\ cm=image\ distance$

Image will be formed towards negative x-axis 30 cm away from the pole.

Magnification (m) is the negative ratio of mage distance and object distance:

⇒ $m=-\frac{image\ distance}{object\ distance}$

⇒ $m=-\frac{(-30)}{(-15)}$

⇒ $m=-2$

The focal length of the concave mirror, is of 10 cm, object distance is 30 cm and magnification is -2.

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2 years ago

You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.

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Answer

given,

diameter of planet = 1.8 x 10⁷ m

radius of planet = 0.9 x 10⁷ m

time period = 22.3 hours

the planet orbits 2.2 x 10¹¹ m period of 402 earth days.

acceleration= 12.2 m/s²

we know

$g = \dfrac{GM_{p}}{r^2}$

$M_{p} = \dfrac{gr^2}{G}$

$M_{p} = \dfrac{12.2 \times (0.9 \times 10^7)^2}{6.67 \times 10^{-11}}$

M_p = 1.48 x 10²⁵ Kg

b) Formula to calculate the mass of star

$M_{s} = \dfrac{4\pi^2}{GT_s^2}(R^3)$

$M_{s} = \dfrac{4\pi^2}{6.67 \times 10^{-11} \times (402 \times 86400)^2}((2.2 \times 10^{11})^3)$

M_s = 5.22 x 10³³ Kg

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3 years ago

An inductor with L = 9.55 mH is connected across an ac source that has voltage amplitude 49.0 V You may want to review (Pages 10

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The phase angle ф for the source voltage relative to the current the and Frequency is 192.14 H.

Phase angle b/w VL and inductor is 90°

Angular frequency, w = 2 pi f

VL = I XL

Frequency, f = VL/2 pi L I = 49/(2 pi x 4.25 x 0.00955) = 192.14 Hz.

The formula = 2/T yields the angular frequency. In radians per second, the angular frequency is expressed. The frequency, f = 1/T. the reciprocal period. The number of full oscillations per unit of time is given by the motion's frequency, f = 1/T = /2. Angular frequency and velocity are related to displacement and revolution velocity, respectively. full response Angular frequency is a scalar measure of rotation rate, also known as angular speed, radial frequency, circular frequency, and orbital frequency.

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8 months ago