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yanalaym [24]
4 years ago
10

Sometimes students are taught that "air expands as it is heated". And sometimes they are taught that "as air expands it cools".

Under what conditions could the first statement be true? Under what conditions could the second statement be true?
Physics
1 answer:
hram777 [196]4 years ago
7 0

Answer:

Both are true under specific circumstances. And are related to Boyle's law. volume and pressure in a gas are inversely proportional.

Explanation:

There is a tendency to entropy in our reality, that is, in particular true and visible with gases, they tend to occupy the whole space where they are confined, when we heat a volume of gas, then the movement of the particles and in consequence the pressure of the gas increases and to compensate this the volume tends to be increased too, according to Boyle's law. And the opposite happens when the volume is increased, then the pressure is  relieved and since the particles are further one from each other, then the temperature is lower, and therefore it cools down.

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1. A body has a velocity of 72 km/hr. Find its value in m/s.
CaHeK987 [17]

72 Km/hr

= 72000 m/ 60×60 s

= 72000 m/ 3600 s

= 20 m/s

Answer is 20 m/s.

Hope it helps! Please do comment

8 0
3 years ago
The number of kilograms of water in a human body varies directly as the mass of the body. Upper AA 9393​-kg person contains 6262
Pie

Answer:

54 kg

Explanation:

Mass of person = 93 kg = m_p

Mass of water = 62 kg = m_w

Dividing the above two masses we get

\frac{m_p}{m_w}=\frac{93}{62}\\\Rightarrow \frac{m_p}{m_w}=1.5\\\Rightarrow m_p=1.5m_w

Hence, the mass of the person is 1.5 times the mass of the water in them

Now, Mass of person = 81 kg = m_p

m_p=1.5m_w\\\Rightarrow m_w=\frac{1}{1.5} m_p\\\Rightarrow m_w=\frac{1}{1.5} \times 81\\\Rightarrow m_w=54\ kg

So, the mass of water in a person that has mass of 81 kg is 54 kg

3 0
3 years ago
Jessica did an investigation about the states of matter. As part of the investigation, Jessica wanted to change a liquid into a
nika2105 [10]
В общем то что я могу когда ккщ на русском бесплатно без вирусов и бактерий к тебе на меня не будет так же как и все равно не будет так как я не могу найти человека с натуры
3 0
3 years ago
Read 2 more answers
A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air
kozerog [31]

Answer:

h=17m

v=18.6 m/s

Explanation: The question can be solved by applying kinematic equations of motion

Data

u=0

a=g

t=1.9 secs

firstly to calculate the height

s=ut+0.5at^2\\h=ut+0.5at^2\\h=0*1.9+0.5*9.81*1.9^2\\h=17.707 m

to find the final velocity

v=u+at\\v=0+9.81*1.9\\v=18.639

The acceleration graph is straight line of equation y=9.8 as acceleration is constant:

Velocity graph is given by y=9.8x ( y as velocity and x as time):

Displacement graph is given by y=4.9x^2 ( x as time, y as displacement):

These graphs are only applicable from x=0 to x=1.9 ... ignore the other graph sections

5 0
3 years ago
how fast will and in what direction will a 20kg object accelerate if one force pushes at a 30 degree angle and another pushes at
DiKsa [7]

Answer:

|a|=2.83\ m/s^2

\theta=75^o

Explanation:

<u>Net Force And Acceleration </u>

The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by

\vec F_n=m\vec a

The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N

The components of the first force are

\vec F_1=

\vec F_1=\ N

The components of the second force are

\vec F_2=

\vec F_2=\ N

The net force is

\vec F_n=

\vec F_n=\ N

The magnitude of the net force is

|F_n|=\sqrt{14.64^2+54.64^2}

|F_n|=\sqrt{3200}=56.57\ N

The acceleration has a magnitude of

\displaystyle |a|=\frac{|F_n|}{m}

\displaystyle |a|=\frac{56.57}{20}

|a|=2.83\ m/s^2

The direction of the acceleration is the same as the net force:

\displaystyle tan\theta=\frac{54.64}{14.64}

\theta=75^o

5 0
3 years ago
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