1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NeX [460]
3 years ago
13

For a charged hollow metal sphere with total charge Q and radius R centered on the origin: (Determine whether each of the follow

ing statements is correct or incorrect.) The field inside the shell is zero. The field for r > R will be the same as the field of a point charge, Q, at the origin The charge is on the inside surface. Only + charges can be on the outside surface. The E-field on the outside is perpendicular to the surface. Inside the metal the field is strongest.
Physics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

1. The field inside the shell is 0; TRUE

2. The field for r>R will be the same as a field for the point charge Q, at the origin: TRUE

3. only positive charges can be on the outside surface: FALSE (Negative can too!!!)

4. The field on the outside is perpendicular to the surface: TRUE

Explanation:

You might be interested in
A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the
ser-zykov [4K]

Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

From the question we are told that

           The mass  is  m =0.5 kg

            The vertical spring  length is  L = 1.10m

            The unstretched  length is  L_{un} = 1.30m

          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

The spring constant k is mathematically represented as

                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

    Now  substituting values accordingly

                    k =  \frac{4.9}{0.6}

                       = 8.17 N/m

The  elastic potential energy is given as E_{PE} = \frac{1}{2} k D^2

  where D is this the is the displacement  

Since Energy is conserved the total elastic potential energy would be

             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

            E_T = \frac{1}{2} k D_{max}^2 =   \frac{1}{2} k D^2 + \frac{1}{2} mv^2

Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

                 D^2_{max} = 0.9033

                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

5 0
3 years ago
Read 2 more answers
A box experiencing a gravitational force of 600 N is being pulled to the right with force of 250 N. A 25 N frictional force acts
bearhunter [10]

Answer: 0 NEWTONS

Explanation:

6 0
3 years ago
20. A cannon shoots a ball at 38 m/s at an angle of 30°. Ignore the original height of the cannon and assume level ground.
sergij07 [2.7K]
Answer:
a.3.87s
b.127.36m
c.18.4m

Step by step explanation:
Refer to the diagram

5 0
2 years ago
Your friend says that if Newton’s third law is correct, no object would ever start moving. Here is his argument: You pull a sled
m_a_m_a [10]

Answer:

Explanation:

You pull a sled exerting a 50 N force on it , sled also exerts a force on you . These forces are action and reaction force , as per third law of Newton . These two forces are equal and  opposite . But they do not act on the same object so they do not cancel each other . They act on different objects , one on the sledge and the other on you . Due to force on sledge , sledge moves in the direction of force or towards you . You will start moving in opposite direction if frictional force of ground is nil or less .

6 0
2 years ago
The force generated by a single muscle fiber can be increased by increasing is called
mars1129 [50]

Answer:

The force generated by a single muscle fiber can be increased by increasing the frequency of action potentials

Explanation:

The force generated by a muscle fiber is the result of the shortening of the skeletal muscle, and this force is also know as muscle tension. The larger motor units shorten along with the smaller units to produce the muscle force. The time lapsed between the beginning of the action potential in the muscle and the beginning of the contraction is the latent period. Action potential is the result of the difference electrical potential as a result of passage of an impulse along the membrane of a muscle or nerve cell.

4 0
3 years ago
Other questions:
  • Larry, a ten year old, first sees two identical glasses with water at the same level; then, the water from one of the short, wid
    8·1 answer
  • I need help on #9 (it's side ways sorry...)
    14·2 answers
  • State Pascal''s principle. Give and example of its use
    7·1 answer
  • Help please suffering
    5·1 answer
  • An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45° relative to edge of the sidewalk. If it has
    14·1 answer
  • Calculate the focal length (in m) of the mirror formed by the shiny bottom of a spoon that has a 3.40 cm radius of curvature. m
    13·1 answer
  • Convert the unit of 0.00023 kilograms into grams. (Answer in scientific notation)
    8·2 answers
  • PLS HELP ME. A 0.0780 kg lemming runs off a 5.36m high cliff at 4.84 m/s what is it potential energy when it lands?​
    5·1 answer
  • Question 14 (2 points)
    5·1 answer
  • What is the meaning of inversely proportion​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!