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NeX [460]
3 years ago
13

For a charged hollow metal sphere with total charge Q and radius R centered on the origin: (Determine whether each of the follow

ing statements is correct or incorrect.) The field inside the shell is zero. The field for r > R will be the same as the field of a point charge, Q, at the origin The charge is on the inside surface. Only + charges can be on the outside surface. The E-field on the outside is perpendicular to the surface. Inside the metal the field is strongest.
Physics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

1. The field inside the shell is 0; TRUE

2. The field for r>R will be the same as a field for the point charge Q, at the origin: TRUE

3. only positive charges can be on the outside surface: FALSE (Negative can too!!!)

4. The field on the outside is perpendicular to the surface: TRUE

Explanation:

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Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (
alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
Why would a person choosing to take a line of credit want to choose one that charges simple interest
krok68 [10]

Answer:

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8 0
2 years ago
When celery is placed in a glass of pure water the solution inside its cells is _____ compared to the water.?
kow [346]
The correct answer to the question above is hypertonic. When celery is being placed in a glass of pure water, the solution inside its cells is going to appear as hypertonic compared to the water. This means that the cells inside has a higher concentration than outside.
4 0
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Point charge q1 of 30 nC is separated by 50 cm from point charge q2 of -45 nC. As shown in the diagram, point a is located 30 cm
Angelina_Jolie [31]

Answer:

E1 =  2996.667N/C E2 = 11237.5N/C

Explanation:

E1 = kQ1/r^2

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  = 2996.667N/C

E2 = kQ2/r^2

      = 8.99 x 10^9 x 50 x 10^-9/(20x10^-2)^2

      = 11237.5N/C

The direction are towards the point a

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Hope this helps

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