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kvasek [131]
3 years ago
12

A physics student in a hot air balloon ascends vertically at constant speed. Consider the following four forces present in this

situation: 1 = the weight of the hot air balloon 3 = the force of the student pulling on the earth 2 = the weight of the student 4 = the force of the hot air balloon pulling on the student Which two forces form an "action-reaction" pair that obeys Newton's third law?
Physics
1 answer:
Leni [432]3 years ago
3 0

Answer:

The two forces that form an "action-reaction" pair that obeys Newton's third law are forces 2 and forces 3

Explanation:

The force by which student pulls the earth will be equal in magnitude and opposite in direction to the force by which earth pulls the student l.e his weight.

Therefore, the two forces are

3 = the force of the student pulling on the earth and

2 = the weight of the student

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A 1kg skateboard sits at the top of a ramp 20 fr off the ground . How much potential energy does it have ?
Finger [1]

Answer:

196J

Explanation:

Given parameters:

Mass of skateboard  = 1kg

Height off the ground  = 20m

Unknown:

Potential energy  = ?

Solution:

The potential energy is the energy due to the position of a body above the ground.

It is mathematically expressed as:

      Potential energy  = mass x acceleration due gravity x height

     Potential energy  = 1 x 9.8 x 20  = 196J

8 0
3 years ago
Calculate the energy needed to change 200.0 g of ice from -20.0°C to water at 35.0°C.
oksano4ka [1.4K]

it's C  24.94KCAL

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3 years ago
A 20.0-µF capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280
natali 33 [55]

Answer

given,

Capacitance of capacitor = 20.0-µF

Voltage =  150.0-V

inductance = 0.280 m H

a) the oscillation frequency of circuit

f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{LC}}

f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{0.280 \times 10^{-3}\times 20 \times 10^{-6}}}

f = 2126.9 Hz

b) U = \dfrac{1}{2}CV^2

   U = \dfrac{1}{2}(20\times 10^{-6})(150)^2

         U = 0.225 J

c)Current in the inductor

    V = L \dfrac{dI}{dt}

    150 = 0.28 \times 10^{-3} \dfrac{dI}{dt}

    \dfrac{dI}{dt} = 535714

instantaneous rate of change of current is equal to 535714 A/s

 

7 0
3 years ago
17. When people replace systems, even when they still work, this is an example of... *
Law Incorporation [45]

I'm gonna have to guess B) Automation sorry if I get it incorrect

3 0
3 years ago
Read 2 more answers
If the mass of the block is too large and the block is too close to the left end of the bar (near string B) then the horizontal
iVinArrow [24]

Answer:

xcritical = d− m1 /m2 ( L /2−d)

Explanation: the precursor to this question will had been this

the precursor to the question can be found online.

ff the mass of the block is too large and the block is too close to the left end of the bar (near string B) then the horizontal bar may become unstable (i.e., the bar may no longer remain horizontal). What is the smallest possible value of x such that the bar remains stable (call it xcritical)

. from the principle of moments which states that sum of clockwise moments must be equal to the sum of anticlockwise moments. aslo sum of upward forces is equal to sum of downward forces

smallest possible value of x such that the bar remains stable (call it xcritical)

∑τA = 0 = m2g(d− xcritical)− m1g( −d)

xcritical = d− m1 /m2 ( L /2−d)

6 0
3 years ago
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