Answer:
Energy always involves. motion in some form. Matter is an object that that up space so it is. measured in units of space
Explanation:
The answer is a mood disorder
The answer is 294j by puting it in kinetic energy formula.
Answer:
The total momentum is 
Explanation:
The diagram illustration this system is shown on the first uploaded image (From physics animation)
From the question we are told that
The mass of the first object is 
The speed of the first mass is 
The mass of the second object is 
The speed of the second object is assumed to be 
The total momentum of the system is the combined momentum of both object which is mathematically represented as

substituting values


Answer:
The power dissipated in the 3 Ω resistor is P= 5.3watts.
Explanation:
After combine the 3 and 6 Ω resistor in parallel, we have an 2 Ω and a 4 Ω resistor in series.
The resultating resistor is of Req=6Ω.
I= V/Req
I= 2A
the parallel resistors have a potential drop of Vparallel=4 volts.
I(3Ω) = Vparallel/R(3Ω)
I(3Ω)= 1.33A
P= I(3Ω)² * R(3Ω)
P= 5.3 Watts