Answer:
A 65
Step-by-step explanation:
The angle formed by two chords is 1/2 the sum of intercepted arcs
x = 1/2 (51+79)
x = 1/2(130)
x =65
If you were to round it, a possible answer could be 9,997
Answer:
V ≈ 5575.28
Step-by-step explanation:
First, you will get the radius and in order to get the radius you have to divide 22/2 which will give you 11 then you will plug 11 into the formula which is V= 4/3 pi r^3 then it will come out as this V=4/3 pi 11^3 and if you plug that into the calculator it will give you an answer of 5575.28.
Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 8.59, \sigma = 0.63](https://tex.z-dn.net/?f=%5Cmu%20%3D%208.59%2C%20%5Csigma%20%3D%200.63)
Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{9.08 - 8.59}{0.63}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B9.08%20-%208.59%7D%7B0.63%7D)
![Z = 0.78](https://tex.z-dn.net/?f=Z%20%3D%200.78)
has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.