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marta [7]
3 years ago
15

The gravitational force exerted by a proton on an electron is 2x1039 times weaker than the electric force that the proton exerts

on an electron? True or False? explain.
Physics
1 answer:
pickupchik [31]3 years ago
7 0

To solve this problem we will rely on the theorems announced by Newton and Coulomb about the Gravitational Force and the Electrostatic Force respectively.

In the case of the Force of gravity we have to,

F_g = G\frac{m_pm_e}{d^2}

Here,

G = Gravitational Universal Constant

m_p = Mass of Proton

m_e = Mass of Electron

d  = Distance between them.

F_g = (6.673*10^{-11} kg^{-1} \cdot m^3 \cdot s^{-2}) (\frac{(1.672*10^{-27}kg)(9.109*10^{-31})}{(52.9pm)^2})

F_g = 3.631*10^{-47}N

In the case of the Electric Force we have,

F_e = k\frac{q_pq_e}{d^2}

k = Coulomb's constant

q_p = Charge of proton

q_e = Charge of electron

d = Distance between them

F_e = (9*10^9N\cdot m^2 \cdot C^{-2})(\frac{(1.602*10^{-19}C)(1.602*10^{-19}C)}{(52.9pm)^2})

F_e = 82.446*10^{-9}N

Therefore

\frac{F_e}{F_g} = 2.270*10^{39}

We can here prove that the statement is True

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Achargingbullelephantwithamassof5240kgcomesdi- rectly toward you with a speed of 4.55 m/s. You toss a 0.150-kg rubber ball at th
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Answer:

Given:

Mass of elephant = 5240 kg

The initial speed of the elephant = 4.55 m/s

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Inital speed of the rubber ball, v = 7.81 m/s

On substitution  in V_{2f} = [\frac{2m_{1} }{m_{1} +m_{2} } ]V_{1f} + [\frac{m_{2}-m_{1}}{m_{1}+m_{2}  } ] v_{2f}

V_{2f} = [\frac{2*5240_{} }{5240_{} +0.15_{} } ](-4.55_{}) + [\frac{0.15_{}-5240_{}}{5240_{}+0.15_{}  } ] (7.81_{})

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8 0
3 years ago
Q5: An ice skater moving at 12 m/s coasts
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u = 0.077

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A particle that is moving along a straight line accelerates from 40 cm/s to 20 cm/s in 5.0 s and then has a constant acceleratio
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Answer:

Average speed,  v_{avg}=43.33\ \rm cm/s

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Given:

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<u>First case</u>

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2as=v^2-u^2\\2as=20^2-40^2\\as=-600\\

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v_{avg}=\dfrac{150+240}{5+4}\\v_{avg}=43.33\ \rm cm/s

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