Answer: The value of equilibrium constant for new reaction is 
Explanation:
The given chemical equation follows:
The equilibrium constant for the above equation is 
We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:
The equilibrium constant for this reaction will be the cube of the initial reaction.
If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.
The value of equilibrium constant for reverse reaction is:
Hence, the value of equilibrium constant for new reaction is
To solve the question you use the following formula:
concentration (1) × volume (1) = concentration (1) × volume (1)
3 M × volume (1) = 1.8 M × 50 mL
volume (1) = (1.8 M × 50 mL) / 3 M = 30 mL
Answer:
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Answer:
A. A galvanic cell generates electrical current, and an electrolytic cell uses electrical energy to cause redox reactions to occur.
Explanation:
A galvanic cell produces electrical energy through the conversion of chemical energy whereas the electrolytic cell carries out the conversion of the electrical energy/current supplied to it into chemical energy. The reaction that takes place in the galvanic cell is spontaneous which is responsible for the electrical energy that is produced. The redox reaction in the electrolytic cell is not spontaneous. Electrical energy has to be supplied to it in order to initiate the reaction.
Answer:
B. How much energy it takes to heat a substance
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity. For example,
The specific heat capacity of oil is 1.57 j/g. K and for water is 4.18 j/g.K. So, water take a time to increase its temperature by one degree by absorbing more heat while oil will heat up faster by absorbing less amount of heat.
Consider that both oil and water have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,
For oil:
Q = m.c. ΔT
Q = 5 g× 1.67 j/g K × 15 K
Q = 125.25 j
For water:
Q = m.c. ΔT
Q = 5 g× 4.18 j/g K × 15 K
Q = 313.5 j
we can observe that water require more heat which is 313.5 j to increase its temperature.
