The ionic equation represents the element in cation and anionic form. The equation is given as OH⁻ + 2H⁺ → 2H₂O. Thus, option A is correct.
<h3>What is the ionic equation?</h3>
The ionic reaction equation is the representation of the chemicals dissociated as the ions in an aqueous solution. The ionic reaction is given as the cations and anions dissociated from the respective molecule or compound.
The ionic equation between potassium hydroxide and sulfuric acid is shown as,
2K⁺ + OH⁻ + 2H⁺ + SO₄²⁻ → 2H₂O + 2K⁺ + SO₄²⁻
It can also be written as,
Net ionic equation: OH⁻ + 2H⁺ → 2H₂O
Here, others are eliminated as they are spectator ions.
Therefore, option A. OH⁻ + 2H⁺ → 2H₂O is the net ionic equation.
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Answer:
Molarity of NaOH = 1.8 M.
Explanation:
From the question given above, the following data were obtained:
Mass of NaOH = 36 g
Molar mass of NaOH = 40 g/mol
Volume = 500 mL
Molarity of NaOH =?
Next, we shall determine the number of mole in 36 g of NaOH. This can be obtained as follow:
Mass of NaOH = 36 g
Molar mass of NaOH = 40 g/mol
Mole of NaOH =?
Mole = mass / molar mass
Mole of NaOH = 36 / 40
Mole of NaOH = 0.9 mole
Next, we shall convert 500 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
500 mL = 500 mL × 1 L / 1000 mL
500 mL = 0.5 L
Finally, we shall determine the molarity of NaOH. This can be obtained as follow:
Mole of NaOH = 0.9 mole
Volume = 0.5 L
Molarity of NaOH =?
Molarity = mole / Volume
Molarity of NaOH = 0.9 / 0.5
Molarity of NaOH = 1.8 M
Explanation:
I think the answer is 2nd
Answer:
Hence, 15.99 g of solid Aluminum Sulfate should be added in 250 mL of Volumetric flask.
Explanation:
To make 0.187 M of Aluminum Sulfate solution in a 250 mL (0.250 L) Volumetric flask
The molar mass of Aluminum Sulfate = 342.15 g/mol
Using the molarity formula:-
Molarity = Number of moles/Volume of solution in a liter
Number of moles = Given weight/ molar mass
Molarity = (Given weight/ molar mass)/Volume of solution in liter
0.187 M = (Given weight/342.15 g/mol)/0.250 L
Given weight = 15.99 g
Answer:
Mass in kg = 4.7*10^19 kg
Mass in tons = 5.2*10^16 tons
Explanation:
<u>Given:</u>
Total volume of sea water = 1.5*10^21 L
Mass % NaCl in seawater = 3.1%
Density of seawater = 1.03 g/ml
<u>To determine:</u>
Total mass of NaCl in kg and in tons
<u>Calculation:</u>
Unit conversion:
1 L = 1000 ml
The volume of seawater in ml is:
To convert mass from g to Kg:
1000 g = 1 kg
To convert mass from g to tons:
1 ton = 9.072*10^6 g
