Al- 28
B- 11
C- 14
Sc- 46
Na- 24
Mass number= proton+neutrons
819 ml is the volume the gas will occupy at 30.0°C.
Explanation:
Data given:
initial volume of the gas V1 = 590 ml
initial temperature of the gas T1 = -55 degrees OR 218.15
final volume of the gas V2 = ?
final temperature of the gas T2 = 30 degrees OR 303.15
Charles' Law equation is used to calculate the volume of gas at 30 degrees from the data given in the question.
= 
V2 = 
V2 = 
V2 = 819 ml
The final volume of the gas would be 819 ml.
C. The design would not be cost-efficient; the plane would require more fuel due to increased thrust from higher drag.
Answer
27.7 moles
Explanation:
Data Given:
Chemical formula of Calcium carbonate = CaCO₃
no. of atoms of CaCO₃ = 8.35 x 10²⁵ atoms
moles of CaCO₃= ?
Solution
First convert number of atoms to number of molecules
As
we have 5 atoms per molecule then how many molecules will be for 8.35 x 10²⁵ atoms
So, apply unity formula
5 atoms ≅ 1 molecule of CaCO₃
8.35 x 10²⁵ atoms ≅ X molecule of CaCO₃
by doing cross multiplication
X molecule of CaCO₃ = 8.35 x 10²⁵ atoms x 1 molecule / 5 atoms
X molecule of CaCO₃ = 1.67 x 10²⁵ molecule
Formula will be used
no. of moles = no. of molecules / Avogadro's number . . . . (1)
Where
Avogadro's number = 6.022 x 10²³ molecules/mol
So,
Put values in equation 1
no. of mole = 1.67 x 10²⁵/ 6.022 x 10²³ (molecules/mol)
no. of mole = 27.7 moles
So,
moles of CaCO₃ = 27.7 moles
It is called the nitrogen cycle- nitrogen gas gets transformed into nitrates through nitrogen fixation.
