Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol
Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol
Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
= (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
= 176.15 kJ - 84.78 kJ = 91.38 kJ
The correct answer C - acceleration
Explanation:
retype the equation.
the equation is'nt complete
Answer:
The volume is 406 mL
Explanation:
Step 1: Data given
Molarity of a zinc nitrate solution = 1.3 M
Mass of zinc nitrate = 100 grams
Molar mass of Zn(NO3)2 = 189.36 g/mol
Step 2: Calculate moles Zn(NO3)2
Moles Zn(NO3)2 = mass Zn(NO3)2 / molar mass Zn(NO3)2
Moles Zn(NO3)2 = 100.0 grams / 189.36 g/mol
Moles Zn(NO3)2 = 0.5281 moles
Step 3: Calculate volume
Molarity = moles / volume
Volume = moles / molarity
Volume = 0.5281 moles / 1.3 M
Volume = 0.406 L = 406 mL
The volume is 406 mL
Noble gas notation for molybdenum:
[Kr] 4d^5 5s^1