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Alex_Xolod [135]
3 years ago
12

1500 L has how many significants figures

Chemistry
1 answer:
Luda [366]3 years ago
3 0

Answer:

It has 2

Explanation:

The significant figures are 1 and 5!

Hope this helps:)

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Consider the following molecules with trigonal planar geometry. Carbonate (CO32−) and nitrate (NO3−) both exhibit resonance, whe
Arturiano [62]

Answer:

See explanation.

Explanation:

Carbonate and Nitrate: during double resonance the double bond revolves around each oxygen. This creates an atmosphere equal to each O-C-O link, then all 1200.

Phosgene: being that the atmosphere changes for each atom the bond angle should be 120, but a deviation occurs, since oxygen is more electronegative than Cl and O, so it is doubly linked. The Cl-C-O bond increases because the O and Cl repel each other, and a 124.3 bond angle is created between Cl-C-O, decreasing the Cl-C-Cl bond angle to 111.4 degrees.

See the result in the attached graph.

Hope this helps!

8 0
3 years ago
describe an example of how humans used selective breeding in plants,and explain how that has benefited us
Crank
The plants give out oxygen so for us humans will live
6 0
4 years ago
Is the aqueous solution of each of these salts acidic, basic, or neutral? (a) cr(no3)3 acidic basic neutral (b) nahs acidic basi
melisa1 [442]
1) chromium(III) nitrate is acidic,  because it is the salt of weak base (chromium(III) hydroxide Cr(OH)₃) and strong acid (nitric acid HNO₃).
2) sodium hydrosulfide is basic, because it is the salt of strong base (sodium hydroxide MaOH) and weak acid (hydrogen sulfide H₂S).
3) zinc acetate is little basic, because zinc hydroxide (Zn(OH)₂) is stronger base than acetic acid (CH₃COOH).

5 0
3 years ago
Read 2 more answers
A sample of nitrogen gas is stored in a 0.500 L flask at 101.3 atm. The gas is transferred to a 0.750
Paladinen [302]

Answer:

67.5 atm

Explanation:

To answer this problem we can use <em>Boyle's law</em>, which states that at constant temperature the pressure and volume of a gas can be described as:

P₁V₁=P₂V₂

In this case:

P₁ = 101.3 atm

V₁ = 0.500 L

P₂ = ?

V₂ = 0.750 L

We input the data:

101.3 atm * 0.500 L = P₂ * 0.750 L

And solve for P₂:

P₂ = 67.5 atm

7 0
3 years ago
A 4.00 g sample of a metal (specific heat = 0.600 J g-1°C-1 is heated to 75 degrees Celcius and then dropped into 165 g of water
Bond [772]

Answer:

28.16 °C

Explanation:

Considering that:-

Heat gain by water = Heat lost by metal

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)

For water:

Mass = 165 g

Initial temperature = 28 °C

Specific heat of water = 4.184 J/g°C

For metal:

Mass = 4.00 g

Initial temperature = 75 °C

Specific heat of water = 0.600 J/g°C

So,  

165\times 4.184\times (T_f-28)=4.00\times 0.600\times (75-T_f)

690360\left(T_f-28\right)=2400\left(75-T_f\right)

692760T_f=19510080

T_f = 28.16\ ^0C

<u>Hence, the final temperature is 28.16 °C</u>

4 0
4 years ago
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