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MariettaO [177]
3 years ago
6

Which of the following is the conjugate of a complex number with 2 as the real part and −8i as the imaginary part? (5 points)

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0
I believe it is 2+8i.
MrMuchimi3 years ago
6 0

Answer:

2+8i is your final answer

Step-by-step explanation:

its choice B

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27x^2y^4÷16yz^4×8z÷9xy^4
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2 years ago
If PQ=8 and Q lies at -13 where could P be located?
choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first.  )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

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Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

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Step-by-step explanation:

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