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3 years ago

50 + 25 pts 75 for right answer

Chemistry

1 answer:

zheka24 [161]3 years ago

3 0

Answer:

soe are appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many other

Explanation:

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Plz someone help me with this!

Genrish500 [490]

4 is sound energy and electrical 5 is nuclear energy 5 is mechanical

4 0

3 years ago

Suppose you start with a solution of red dye #40 that is 3.1 ✕ 10−5 M. If you do four successive volumetric dilutions pipetting

Vanyuwa [196]

Answer:

1.3 × 10⁻¹¹ M

Explanation:

We are going to do 4 successive dilutions. In each dilution, we will apply the dilution rule.

C₁.V₁=C₂.V₂

where,

C₁ and V₁ are concentration and volume of the initial state

C₂ and V₂ are concentration and volume of the final state

<u>First dilution</u>

C₁ = 3.1 × 10⁻⁵ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{3.1\times 10^{-5}M \times 1.00mL }{40.00mL} =7.8 \times 10^{-7}M$

<u>Second dilution</u>

C₁ = 7.8 × 10⁻⁷ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{7.8 \times 10^{-7}M \times 1.00mL }{40.00mL} =2.0 \times 10^{-8}M$

<u>Third dilution</u>

C₁ = 2.0 × 10⁻⁸ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{2.0 \times 10^{-8}M \times 1.00mL }{40.00mL} =5.0 \times 10^{-10}M$

<u>Fourth dilution</u>

C₁ = 5.0 × 10⁻¹⁰ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

$C_{2}=\frac{C_{1}.V_{1}}{V_{2}} =\frac{5.0 \times 10^{-10}M \times 1.00mL }{40.00mL} =1.3 \times 10^{-11}M$

4 0

3 years ago

__________ bonds form between the oxygen and hydrogen within water molecules, whereas __________ bonds form between different wa

Gemiola [76]

Answer:

A. Covalent bond

B. Hydrogen bond

Explanation:

4 0

3 years ago

Define - Solute.....

34kurt

The substances that dissolves in water are called solute.

6 0

3 years ago

Calculate the molarity of the two solutions.

daser333 [38]

1. 0.33 M

2. 0.278 M

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

1. 0.350 mol of NaOH in 1.05 L of solution.

n=0.35

V=1.05 L

Molarity :

$\tt M=\dfrac{0.35}{1.05}=0.33$

2. 14.3 g of NaCl in 879 mL of solution.

mol NaCl(MW=58.5 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{14.3~g}{58.5~g/mol}=0.244$

Molarity :

$\tt M=\dfrac{0.244}{0.879~L}\\\\M=0.278$

4 0

2 years ago