Question

The area of a rectangle is 53.3 in2. If the width is 6.5 in, what is the perimeter of the rectangle?

Answer 1

You can find the length from
  A = LW
  53.3 in² = L×(6.5 in)
  (53.3 in²)/(6.5 in) = L = 8.2 in

The perimeter is twice the sum of length and width.
  P = 2(L +W)
  P = 2(8.2 in +6.5 in) = 29.4 in

The perimeter of the rectangle is 29.4 inches.

Answer 2

Area of a rectangle formula
l × w 
6.5 is our width you already know but 53.3 isn't the length so really
you are trying to solve for l, so l × 6.5 = 53.3
when you get that answer you should get 8.2

Now .. you already have the width and the length so you hook in 6.5(w) + 6.5(w)+ 8.2 (l)+ 8.2(l) 
6.5 + 6.5 gives you 13 and 
8.2 + 8.2 gives you 16.4
Adding both up you get the final answer/ perimeter 29.4 inches