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tigry1 [53]
3 years ago
8

Bill and Julie observe the size of the opening of a laser and compare it with the size of a bright spot on the wall toward which

it points. They discover that the spot on the wall is larger than the opening of the laser. Julie says that the spot on the wall is bigger than the laser opening because some light from the laser goes in all directions while most light travels straight to the wall. She suggests the following picture to illustrate her reasoning: Bill disagrees and says that light travels in a straight line and then "splashes" like water from a water hose when it hits the wall. He suggests the following picture to illustrate his reasoning: Describe the design of an experiment that you could perform to decide if one or both models should be rejected. Be sure to make a prediction of the outcome of your experiment based on both models (i.e., 2 predicted outcomes, one for each model).

Physics
1 answer:
belka [17]3 years ago
4 0

Answer:

attached below

Explanation:

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A sport car moving at constant speed travels 110m in 5.0 s. if it then brakes and comes to a stop in 4.0 s, what is the magnitud
stiks02 [169]
D = 110 m,  t = 5 s
v o = 110 cs : 5 m = 22 m/s
-------------------------------------
v = v o - a t
v = 0 m/s,  v o =  22 m/s,  t = 4 s
0 = 22 - 4 a
4 a = 22
a = 22 : 4
a = 5.5 m/s²
g = 9.80 m/s²
9.80 : 5.5 = 0.56 
Answer:
The magnitude of its acceleration is 5.5 m/s or 0.56 g. 
7 0
3 years ago
A 1.0-kg ball has a velocity of 12 m/s downward just before it strikes the ground and bounces up with a velocity of 12 m/s upwar
Nezavi [6.7K]

Answer:

The change in momentum of the ball is 24 kg-m/s  

Explanation:

It is given that,

Mass of the ball, m = 1 kg

Initial velocity of the ball, u = -12 m/s (in downwards)

Final velocity of the ball, v = +12 m/s (in upward)

We need to find the change in momentum of the ball.

Initial momentum of the ball, p_i=mu=1\ kg\times (-12\ m/s)=-12\ kg-m/s

Final momentum of the ball, p_f=mv=1\ kg\times (12\ m/s)=12\ kg-m/s

Change in momentum of the ball, \Delta p=p_f-p_i

\Delta p=12-(-12)=24\ kg-m/s

So, the change in momentum of the ball is 24 kg-m/s. Hence, this is the required solution.

3 0
3 years ago
Suppose a scoentist was able to construct a barometer with a liquid being denser than mercury , then how high would the liquid r
ki77a [65]

Answer:

the liquid has less height than the mercury

      h_{ liquid} = \frac{\rho_{Hg} }{\rho_{liqid}}  \  h_{Hg}

Explanation:

The pressure as a function of the height is given by

        P = ρ g h

where ρ is the density of the liquid, g the acceleration of gravity and h the height reached by the column of the liquid

In that case they say that the pressure is the standard one that is P = 1.01 10⁵ Pa = 760 mmHg

The first way to give the pressure is in SI units and the second way is the height that the mercury column reaches

In the case of building a barometer with a liquid that has a density greater than that of mercury

            ρ_liquid > ρ_Hg

             

the pressure

              P =ρ_lquid g h_liquid

if we have the same pressure

            ρ_{Hg} g h_{Hg} = ρ_{liquid}  g h_{liquid}

            h_{ liquid} = \frac{\rho_{Hg} }{\rho_{liqid}}  \  h_{Hg}

therefore the liquid has less height than the mercury

7 0
3 years ago
One similarity between work and power is that in order to calculate both you must know
svetoff [14.1K]
D.) In order to calculate both of them, we must know the "FORCE" on the system.
8 0
3 years ago
Read 2 more answers
What is shown in the diagram?
Sav [38]

Answer:

an electromagnet

Explanation:

4 0
3 years ago
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