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stepan [7]
3 years ago
6

Write A balanced equation showing the formation of copper (II) nitrite from its elements

Chemistry
1 answer:
34kurt3 years ago
4 0

Answer:

Cu(s) + N₂(g) + 2O₂(g) ⟶ Cu(NO₂)₂(s)

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Sodium metal reacts with water to produce hydrogen gas according to the following equation: 2Na(s) + 2H2O(l)2NaOH(aq) + H2(g) Th
Maru [420]

Answer:

Number of moles of sodium reacted = 0.707 moles

Explanation:

P(H₂) = P(T) – P(H₂O)

P(H₂) = 754 – 17.5 = 736.5 mm Hg

Use the ideal gas equation which

PV= nRT, where P is the pressure V is the volume, n is the number of moles R is the Gas Constant and T is temperature

<u>Re- arrange to calculate the number of moles and using the data provided</u>

n = P x V/R x T

n =736.5 x 8.77/62.36367 x (mmHg/mol K) x (20 + 273)

n = 0.35348668

n = 0.353 moles H₂

<u>from the equation we know that</u>

0.353 mole H₂ x 2mole Na/1mole H₂, So

0.353 x 2 = 0.707 mole Na

The number of moles of Sodium metal reacted were 0.707 moles.

3 0
3 years ago
Consider this chemical equation:
11Alexandr11 [23.1K]

Answer:

the answer is very correct as AgNO3 and Cu(NO3)2

8 0
3 years ago
Read 2 more answers
How many moles are present in 2.7 liters of Argon gas at STP?
Neko [114]

6.9 cause argon is a proactive system that can be sick

4 0
2 years ago
For each pair, predict which molecule has the greater molar entropy under the same conditions (assume gaseous species).c o 2, ca
larisa [96]
I used to know this. I don't really remember but is used to know it. Im in 6th grade now
8 0
3 years ago
A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
masha68 [24]

The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

For first order ln[A]=−kt+ln[A]o

45% complete, 55% remains

A = 0.55

Ao = 1

Input the value :

ln A = -kt + ln Ao

ln 0.55 = -k.65 + ln 1

-0.598=-k.65

k = 9.2 x 10⁻³ s⁻¹

The half life :

t1/2 = (ln 2) / k

t1/2 = 0.693 : 9.2 x 10⁻³

t1/2 = 75.3 s

3 0
2 years ago
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