2 years ago

How to find the range of a logromithic function?

1 answer:

5 0

Since the logarithmic function is the inverse of the exponential function, the domain of the logarithmic function is the range of the exponential function and that works the same both ways.

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Solve <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%20%7D%7B4%20-%20x%7D%20%3D%20%5Cfrac%7B5%7D%7B%284%20%2B%20x%29%7D%20

lisov135 [29]

$Domain:\\4-x\neq0\ \wedge\ 4+x\neq0\\x\neq4\ \wedge\ x\neq-4\\\\\dfrac{4}{4-x}=\dfrac{5}{4+x}\qquad\text{cross multiply}\\\\4(4+x)=5(4-x)\qquad\text{use distributive property}\\\\(4)(4)+(4)(x)=(5)(4)+(5)(-x)\\\\16+4x=20-5x\qquad\text{subtract 16 from both sides}\\\\4x=4-5x\qquad\text{add 5x to both sides}\\\\9x=4\qquad\text{divide both sides by 9}\\\\\boxed{x=\dfrac{4}{9}}$

6 0

2 years ago

Simplify this expression 4x(7x^2) A 11x^2 B. 28x^2 C. 11x^3 D. 28x^3

slega [8]

Answer:

28 x^3

Step-by-step explanation:

4x(7x^2)

4 * x* 7* x*x

4*7 x*x*x

28 x^3

7 0

3 years ago

Read 2 more answers

2/3 (5 x 4) ÷ 3 + 6/7 I divided 3/2 is 1.5*(20)=30/3=10+1.16=11.16 is that correct not so good in math

Assoli18 [71]

$\frac{2}{3}(5*4):3+ \frac{6}{7} = \\ \\ \frac{2}{3}*20:3+ \frac{6}{7} = \\ \\ \frac{40}{3}:3+ \frac{6}{7} = \\ \\\frac{40}{9}+ \frac{6}{7}= \\ \\ \frac{40*7+6*9}{7*9}= \\ \\\frac{280+54}{63}= \\ \\ \frac{334}{63} = \\ \\ 5 \frac{19}{63} \ \ \ [as \ a \ mixed \ fraction] \\ \\ \approx 5.3 \ \ \ [as \ a \ decimal\ fraction \ to \ the \ nearest \ tenth]$