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3 years ago

Select whether the triangle is inscribed in the circle, circumscribed about the circle, or neither.

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

6 0

Answer:

Neither

Step-by-step explanation:

The answer is neither because all three sides of the triangle are supposed to be touching the circle for it to be circumscribed about the circle.

By the way, on my assignment I clicked "circumscribed about the circle" and I got it wrong. But now I understand why I got it wrong! Also, the answer key showed that it is "neither", so don't worry that this answer might be wrong! :)

Ganezh [65]3 years ago

3 0

Neither inscribed in the circle, nor circumscribed about it! 2 if the sides of the triangle are TANGENT to the circle, which means just touching at one point

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Can you help me please?! :)

UkoKoshka [18]

The answer is A
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2 years ago

In this figure m<3=130 What is m<6 ?

Georgia [21]

Answer: $m\angle6=50\°$

Step-by-step explanation:

You can observe in the figure two parallel lines that are intersected by a transversal and several angles are formed.

The angles m∠3 and m∠6 are located inside the parallel lines and on one side of the transversal, this angles are known as "Consecutive interior angles" and they are supplementary (which means that they add up 180°).

Therefore, you know that:

$m\angle3+m\angle6=180\°$

So you can substitute m∠3=130° and solve for m∠6. Then you get:

$130\°+m\angle6=180\°\\m\angle6=180\°-130\°\\m\angle6=50\°$

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3 years ago

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The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10

Rama09 [41]

Answer:

a) $E(X) = 6.45$

b) $E(X^{2} )= 57.25$

c) $V(X) = 15.648$

d) E(3X + 2) = 21.35

e) $E(3X^{2} +2) = 173.75$

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) $E(X) = \sum xP(x)$

$E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45$

$E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\ E(X^{2} )= 57.25$

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$E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35$

$E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75$

$V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832$

$E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45$

$V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648$

6 0

3 years ago

Need help with this question.

Iteru [2.4K]

Take 3÷2.6=1.153846repeating. So around $1.15. To check you can take the decimal point times by 2.6 and it will give you three.

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3 years ago

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Greeley [361]

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3 years ago

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