Answer:
HNO3(aq) + OH-(aq) → NO3-(aq) + H2O(l)
Explanation:
According to Bronsted-Lowry theory, an acid is a substance that donates a proton (H+) and produces a conjugate base while a base is a molecule or ion which accepts the proton.
An example of Bronsted-Lowry acid and base is Nitric acid, HNO3 and hydroxide ion, OH- respectively as shown in the given reaction.
Thus, the nitric acid acts as an acid by donating a proton to the hydroxide ion which accepts it, thus producing nitrate ion, NO3- as a conjugate base, while OH- produces H2O as a conjugate acid.
When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M
The reaction of neutralization of HNO₃ with NaOH is
HNO₃ + NaOH → H₂O + NaNo₃
When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -
With the mole and volumes, we can find molarity as follows:
Moles of NaOH = moles HNO₃
⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH
=0.014 mol HNO₃
Molarity: -

= 0.041 M
Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.
Learn more about molarity: brainly.com/question/8732513
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