Question

A cylindrical container with 25 ft in diameter is filled to a depth of 22 ft with gasoline (S.G.-0.68). Find the weight of the gasoline and the number of gallons that exist in the tank.

Answer 1

Answer:

Weight of gasoline = 2039.93 kN

Volume = 80783.80 gallon

Explanation:

Volume = Base area x Depth

$\texttt{Base area = }\frac{\pi d^2}{4}=\frac{\pi \times 25^2}{4}=490.88ft^2$

Depth = 22 ft

Volume = 490.88 x 22 = 10799.22 ft³ = 10799.22 x 0.0283168 = 305.8 m³

Density of gasoline = 680 kg/m³

Mass of gasoline = 305.8 x 680 = 207943.65 kg

Weight of gasoline = 207943.65 x 9.81 = 2039.93 kN

We have 1 m³ = 264.172 gallon

            305.8 m³ = 305.8 x 264.172 = 80783.80 gallon