Answer:
K= 95.4 J
Explanation:
For this exercise we must use the conservation of mechanical energy.
We set a reference system on the floor.
Starting point. Higher
Em₀ = U = m g h
Final point. Just before taking the floor
Em_f = K = ½ m v²
energy is conserved because there is no friction
Em₀ = Em_f
mg h = K
The height is
- h = y -y₀
h = 0- y₀
let's calculate
K = 3.23 (-9.81) (-3.01)
K= 95.4 J
The answer is 28.5 decaliters. Hope this helps
Answer:A satellite maintains its orbit by balancing two factors its velocity the speed it takes to travel in a straight line and the gravitational pull that Earth has on it. A satellite orbiting closer to the Earth requires more velocity to resist the stronger gravitational pull.
Explanation:
75 percent (calculated percentage %) of what number equals 27? Answer: 36.
Answer:
If by 1.5 MJ you mean 1.5E6 Joules then
W = P t = power X time
W / t = P power
P = 1.5E6 J / 600 sec = 2500 J / s
P = I V
a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps
b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs
c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules
