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Sauron [17]
3 years ago
13

PLS HELP!!! A 1200-kg whale swims horizontally to the right at a speed of 6.0 m/s. It suddenly collides directly with a stationa

ry seal of mass 280 kg. The seal grabs onto the whale and holds fast. What is the momentum of these two sea creatures just after their collision? You can neglect any drag effects of the water during the collision.
A) 0.00 kg • m/s

B) 1680 kg • m/s

C) 2000 kg • m/s

D) 6000 kg • m/s

E) 7200 kg • m/s
Physics
1 answer:
Fittoniya [83]3 years ago
7 0

Answer:

7200 kg.m/s

Explanation:

According the law of conservation of linear momentum, the sum of momentum before and after collision are equal.

Using this principle, the sum of initial momentum will be given as p=mv where p is momentum, m is mass and v is velocity

Initial momentum

Mass of whale*initial velocity of whale + mass of seal*initial seal velocity

Since the seal is initially stationary, its velocity is zero. By substitution and taking right direction as positive

Initial momentum will be

1200*6+(280*0)=7200 kg.m/s

Since both initial and final momentum should be equal, hence the final momentum will also be 7200 kg.m/s

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Answer:

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Explanation:

You have the following expression for the acceleration of the projectile:

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To find the value of the constant c you use the following formula:

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You replace the expression (1) into the expression (2):

v^2=2(cs)\Delta s

You do the constant c in the last equation, then you replace the values of v, s and Δs:

c=\frac{v^2}{2s\Delta s}=\frac{(200m/s)^2}{2(3m/s^2)(1.5m)}=4444.44

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3 years ago
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4 0
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Answer:

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Explanation:

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4 years ago
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Answer:

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Hope it helped u if yes mark me BRAINLIEST!

Tysm!

I would appreciate it!

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