An icicle falls off of a skyscraper from rest and falls for 34 seconds. How fast will that icicle be moving after that time? Sho
1 answer:
Answer:
<em>The icicle will be moving at 333.54 m/s</em>
Explanation:
<u>Free Fall Motion </u>
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is .
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The icicle falls from rest for 34 seconds. We need to find the speed after that time:
vf = 9.81*34
vf = 333.54 m/s
The icicle will be moving at 333.54 m/s
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Answer:
141.56 N.
Explanation:
Data given:
Weight of the box= 200.2 N
Angle with the horizontal= 37.1°
Solution;
Gravitational force on the box, = weight of the box
= 200.2 N
Component of gravitational force along plane = ( ∅ )
= W * (sin∅)
= (200.1) * sin (37.1°)
= 141.56 N
<h2>Hello!</h2>
The answer is:
The first option, the walker traveled 360m more than the actual distance between the start and the end points.
Why?
Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).
So, calculating we have:
Traveler:
Actual distance between the start and the end point (displacement):
Now, to calculate how much farter did the traveler walk, we need to use the following equation:
Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.
Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.
Have a nice day!