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skelet666 [1.2K]
3 years ago
8

Consider the motion of a bullet that is fired from a rifle 6 m above the ground in a northeast direction. The initial velocity o

f the bullet is (200, 200, 0) . Assume the​ x-axis points​ east, the​ y-axis points​ north, the positive​ z-axis is vertical​ (opposite g), the ground is​ horizontal, and only the gravitational force acts on the object.
a. Find the velocity and position vectors for t >_0.
Physics
1 answer:
timurjin [86]3 years ago
6 0

Answer:

The time taken for the bullet to hit the ground: 1.1059

Final Velocity Vector: (200, 200, -10.85)

Final Position Vector: (221.18, 221.18, 0)

Explanation:

For this problem, lets start with finding the time it takes for the bullet to hit the ground. Since it was fired horizontally, it's initial vertical velocity is zero. This is also it's velocity in the z direction.

Time taken for the bullet to hit the ground:

s=u*t +\frac{1}{2} (a*t^2)

here, s = -6 m

u = 0 (initial velocity)

a = -9.81

Solving for t, we get 1.1059 seconds.

In this time, the position change in the x and y axis will be:

x axis: 200 * 1.1059 = 221.18

y axis: 200 * 1.1059 = 221.18

Thus the final position vector will be:

(221.18 , 221.18 , 0)

Note the zero in the z direction is because ground is located at 0.

Let's find the final z velocity as well for the velocity vector:

v^2-u^2=2*a*s

v^2=2 * 9.81 * 6

v = 10.85 m/s (final velocity)

The final velocity vector becomes:

(200, 200, -10.85)

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Explanation:

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In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.  She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.

0.4 miles = 0.64 km

displacement = 0.7-0.3+0.64 = 1.04 km

(b) Average velocity = total displacement/total time

t = 15 min = 0.25 hour

v=\dfrac{1.04\ km}{0.25\ h}\\\\v=4.16\ km/h

Hence, this is the required solution.

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7351.35Hz

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= 7351.35hz

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Which of the following. Chemical represent the law of conservation of Matter?
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The answer is first one 1...

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In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x= 5.0 cos
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Answer:

a)   x = 4.33 m ,   b)  w = 2 rad / s ,  f = 0.318 Hz ,  c) a = - 17.31 cm / s²,  

d) T =  3.15 s,  e)  A = 5.0 cm

Explanation:

In this exercise on simple harmonic motion we are given the expression for motion

          x = 5 cos (2t + π / 6)

they ask us for t = 0

a) the position of the particle

      x = 5 cos (π / 6)

      x = 4.33 m

remember angles are in radians

 

b) The general form of the equation is

          x = A cos (w t + Ф)

when comparing the two equations

         w = 2 rad / s

angular velocity and frequency are related

          w = 2π f

           f = w / 2π

           f = 2 / 2pi

           f = 0.318 Hz

c) the acceleration is defined by

      a == d²x / dt²

      a = - A w² cos (wt + Ф)

for t = 0 ,  we substitute

      a = - 5,0 2² cos (π / 6)

      a = - 17.31 cm / s²

d) El period is

          T = 1/f

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Electric force is given as the product of charge and electric field strength:

F = qE

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E = Electric field strength

Force is generally given as:

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