The magnitude of perpendicular vectors can be determined using ....

A rocket of initial mass 115 kg (including all the contents) has an engine that produces a constant vertical force (the thrust)

sweet-ann [11.9K]

Answer:

Part (i) the initial acceleration of the rocket is 6.98 m/s²

Part(ii) the floor pushes on the power supply at 120m altitude by a force of 31.68 N

Explanation:

Part (i) the initial acceleration of the rocket.

For the rocket to accelerate, the force applied to it must overcome gravitational force due to its own weight.

$F_{Net} = M(a+g)\\\\1930 = 115(a+9.8)\\\\a +9.8 =\frac{1930}{115} \\\\a +9.8 = 16.78\\\\a = 16.78-9.8\\\\a = 6.98 \frac{m}{s^2}$

Part(ii) how hard the floor pushes on the power supply at 120 m altitude

At 120 m height, the acceleration of the rocket is 6.98 m/s², which is the same as the power supply.

given force on power supply;

F = 18.5 N

Applying Newton's second law of motion, the mass of the power supply = 18.5/9.8

= 1.888 kg

The force on power supply at this altitude = m(a+g)

= 1.888(6.98 +9.8)

= 1.888(16.78)

= 31.68 N

Therefore, the floor pushes on the power supply at 120 m altitude by a force of 31.68 N

4 0

4 years ago

A 70-kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.3 m/s. Neglect air resistan

yKpoI14uk [10]

Answer:

$h_{B} = 6.083\,m$

Explanation:

Let assume that pole vaulter begins running at a height of zero. The pole vaulter is modelled after the Principle of Energy Conservation:

$K_{A} = K_{B} + U_{g,B}$

$\frac{1}{2}\cdot m \cdot v_{A}^{2} = \frac{1}{2}\cdot m \cdot v_{B}^{2} + m\cdot g \cdot h_{B}$

The expression is simplified and final height is cleared within the equation:

$\frac{1}{2}\cdot (v_{A}^{2} - v_{B}^{2}) = g\cdot h_{B}$

$h_{B} = \frac{(v_{A}^{2}-v_{B}^{2})}{2\cdot g}$

$h_{B} = \frac{[(11\,\frac{m}{s} )^{2}-(1.3\,\frac{m}{s} )^{2}]}{2\cdot (9.807\,\frac{m}{s^{2}} )}$

$h_{B} = 6.083\,m$

5 0

3 years ago

Some laptops contain a second battery. what is this battery called

Phoenix [80]

I believe this battery is called Sheet battery.
Sheet battery is a flexible, ultra thin energy storage and production device formed by combining nano tubes with a conventional sheet of cellulose based paper. It acts as both a high-energy battery and super-capacitor, combining two components that are separate in traditional electronics.

6 0

3 years ago

What are the first and second object in a gravitational field

vodka [1.7K]

downward force then reaction if you mean what forces

3 0

3 years ago

Two strings with linear densities of 5 g/m are stretched over pulleys, adjusted to have vibrating lengths of 0.50 m, and attache

HACTEHA [7]

Answer:

2.18 kg

Explanation:

The frequency of a wave in a stretched string f = n/2L√(T/μ) where n = harmonic number, L = length of string, T = tension = mg where m = mass of object on string and g = acceleration due to gravity = 9.8 m/s² and μ = linear density of string.

For string 1, its fundamental frequency f is when n = 1. So,

f = 1/2L√(T/μ) = 1/2L√(mg/μ)

Now for string 1, L = 0.50 m, m = 20 kg and μ = 5 g/m = 0.005 kg/m

substituting the values of the variables into f, we have

f = 1/2L√(mg/μ)

f = 1/2 × 0.50 m√(20 kg × 9.8 m/s²/0.005 kg/m)

f = 1/1 m√(196 kgm/s²/0.005 kg/m)

f = 1/1 m√(39200 m²/s²)

f = 1/1 m × 197.99 m/s

f = 197.99 /s

f = 197.99 Hz

f ≅ 198 Hz

For string 2, at its third harmonic frequency f' is when n = 3. So,

f' = 3/2L√(T/μ) = 3/2L√(mg/μ)

Now for string 2, L = 0.50 m, m = M kg and μ = 5 g/m = 0.005 kg/m

substituting the values of the variables into f, we have

f' = 3/2L√(Mg/μ)

f' = 3/2 × 0.50 m√(M × 9.8 m/s²/0.005 kg/m)

f' = 3/1 m√(M1960 m²/s²kg)

f' = 3/1 m√M√(1960 m²/s²kg)

f' = 3/1 m √M × 44.27 m/s√kg

f' = 132.81√M/s√kg

f' = 132.81√M Hz/√kg

Since the frequency of the beat heard is 2 Hz,

f - f' = 2 Hz

So, 198 Hz - 132.81√M Hz/√kg = 2 Hz

132.81√M Hz/√kg = 198 Hz - 2 Hz

132.81√M Hz/√kg = 196 Hz

√M Hz/√kg = 196 Hz/138.81 Hz

√M/√kg = 1.476

squaring both sides,

[√M/√kg] = (1.476)²

M/kg = 2.178

M = 2.178 kg

M ≅ 2.18 kg

8 0

3 years ago