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elena55 [62]
3 years ago
6

It is too coldfor liquidwater to existon thesurface.​

Physics
1 answer:
emmasim [6.3K]3 years ago
7 0

Mars

Explanation:

Mars is believed to be too cold for liquid water to exist on the surface.

  • Mars is known as the red planet and the only planet believed to be able support life in it.
  • It is the last of the inner planets which are made up of rock masses.
  • The atmosphere of mars is very thin.
  • Under average conditions, liquid water will immediately freeze on the surface due to its low atmospheric pressure.

Learn more:

Surface ratio of mars and moon brainly.com/question/6443737

#learnwithBrainly

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Which statement correctly compares the valence electrons for atoms of francium (Fr) and barium (Ba)?
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Francium has fewer valence electrons, but they are in a higher energy level

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When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4250 rpm to 0.00 in 4.00 s. (a) What is the
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Answer:

(a) \alpha=-111.26rad/s

(b) s=4450.6in

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Explanation:

First change the units of the velocity, using these equivalents 1rev=2\pi rad and 1 min =60s

4250rpm(\frac{2\pi rad}{1rev})(\frac{1 min}{60 s} )=445.06rad/s

The angular acceleration \alpha the time rate of change of the angular speed \omega according to:

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\Delta  \omega=\omega_i-\omega_f

Where \omega_i is the original velocity, in the case the velocity before starting the deceleration, and \omega_f is the final velocity, equal to zero because it has stopped.

\alpha=\frac{\Delta \omega}{\Delta t} =\frac{\omega_i-\omega_f}{4}\frac{0-445.06}{4} =\frac{-445.06}{4} =-111.26rad/s

b) To find the distance traveled in radians use the formula:

\theta = \omega_i t + \frac{1}{2} \alpha t^2

\theta = 445.06 (4) + \frac{1}{2}(-111.26) (4)^2=1780.24-890.12=890.12rad

To change this result to inches, solve the angular displacement \theta for the distance traveled s (r is the radius).

\theta=\frac{s}{r} \\s=\theta r

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\frac{890.12}{2\pi}=141.6667

The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance  between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle \gamma=\frac{2\pi}{3}=\frac{360^o}{3}=120 is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which  is also the net displacement):

c^2=a^2+b^2-2abcos(\gamma)

c^2=5^2+5^2-2(5)(5)cos(\frac{2\pi}{3} )\\c^2=25+25+25\\c^2=75\\c=5\sqrt{3}=8.66in

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3 years ago
a cylindrical jar is 10cm long and has a cross sectional area of 36cm. if it is completely filled with a fluid of relative densi
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Answer:

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