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Nookie1986 [14]
3 years ago
9

in example 5.11 of the text the molar volume of n2 at STP is given as 22.42 L/mol how is this number calculatd how does the mola

r volume of h2 at stp compare th te molar volume of n2
Chemistry
1 answer:
Valentin [98]3 years ago
6 0

Answer:

V = 22.42 L/mol

N₂ and H₂ Same molar Volume at STP

Explanation:

Data Given:

molar volume of N₂ at STP = 22.42 L/mol

Calculation of molar volume of N₂ at STP  = ?

Comparison of molar volume of H₂ and N₂ = ?

Solution:

Molar Volume of Gas:

The volume occupied by 1 mole of any gas at standard temperature and pressure and it is always equal to 22.42 L/ mol

Molar volume can be calculated by using ideal gas formula  

                               PV = nRT

Rearrange the equation for Volume

                            V = nRT / P . . . . . . . . . (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

Standard values

P = 1 atm

T = 273 K

n = 1 mole

R = 0.08206 L.atm / mol. K

Now put the value in formula (1) to calculate volume for 1 mole of N₂

                   V = 1 x 273 K x 0.08206 L.atm / mol. K / 1 atm

                   V = 22.42 L/mol

Now if we look for the above calculation it will be the same for H₂ or any gas. so if we compare the molar volume of 1 mole N₂ and H₂ it will be the same at STP.

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Answer:

2.5 %

Explanation:

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Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

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The conversion of mL to L is shown below:

1 mL = 10⁻³ L

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Moles=0.2850 \times {63.30\times 10^{-3}}\ moles

Moles of AgNO_3  = 0.0180405 moles

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Molar mass of Cl^- = 35.453 g/mol

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Alex73 [517]

Answer:

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Explanation:

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