Which two smaller groups is the animals kingdom is divided into

What is a gift offered to a god by killing or burning something? Plz answer I’ll give brainlist and 50 points for free

umka2103 [35]

Answer:

it is a sacrafice to god so the spirtit can go free

Explanation:

4 0

2 years ago

Read 2 more answers

Which statements accurately describe soap? Select one or more:

tia_tia [17]

Answer:

A. Soaps react with ions in hard water to create a precipitate.

B. Soaps are both hydrophobic and hydrophilic.

D. Soaps should be weakly alkaline in solution.

Explanation:

A. Hard water contains <u>magnesium and calcium minerals</u> like calcium and magnesium carbonates, sulfates and bicarbonates. As soon as these minerals come in contact with soap their ions like Mg²⁺ & Ca²⁺ form precipitates.

B. Soap are both hydrophilic and hydrophobic. They reason why they exhibit both the properties is really important for their functionality. The hydrophobic part of soap makes interaction with oil/dust particles while the hydrophilic part makes interaction with water. When the cloth is rinsed the dirt/soap particles are removed from the dirty clothes thereby making them clean.

C. Soaps have alkaline pH i.e. more than 7 that is why they have bitter taste.

5 0

3 years ago

A sample of seawater has 0.075 g of sodium chloride per mL of solution. How many moles of sodium chloride are there per liter of

amm1812

Answer:

1.28 mol

Explanation:

mole = mass/molar mass

n = v/v/cm³

mass = 0. 075g

v = 1dm³ =1000cm³

n= m/MV=0.075/58.44(1000)

n =1.28 mol

4 0

3 years ago

Is MgCO3 organic or inorganic

schepotkina [342]

Its inorganic as MgCO3 is contains no carbon more hydrogen which is a crutial component of all organic compounds

4 0

3 years ago

For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ

Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, $H_3PO_4$ acid and there are three Ka values

$K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}$

The transformation of $H_2PO_4- (aq) to HPO_4^2-(aq)$ is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

= 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

= 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

= -log 6.2x10-8

= 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

= 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0

3 years ago