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3 years ago

Which two smaller groups is the animals kingdom is divided into

Chemistry

1 answer:

Likurg_2 [28]3 years ago

8 0

C pretty sure it’s C because it’s C

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In an anatomy class, a student has been learning about the bones of the body. While taking a test, he needs to identify the ster

storchak [24]

Answer:

The term “flat bone” is somewhat of a misnomer because, although a flat bone is typically thin, it is also often curved. Examples include the cranial (skull) bones, the scapulae (shoulder blades), the sternum (breastbone), and the ribs. Flat bones serve as points of attachment for muscles and often protect internal organs.

HOPE THIS HELPS!!! :D

3 0

3 years ago

Read 2 more answers

SCIENCE HELP ASAP

SpyIntel [72]

The small size and lack of structural tissues in phytoplankton mean that aquatic primary producers achieve faster growth rates and are more nutritious to heterotrophs than their terrestrial counterparts

4 0

3 years ago

Read 2 more answers

3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m

IrinaK [193]

Answer:

$49.45~%$

Explanation:

In this case, we have to start with the chemical reaction:

$C_6H_1_2O~->~C_6H_1_0~+~H_2O$

So, if we start with 10 mol of cyclohexanol ( $C_6H_1_2O$ ) we will obtain 10 mol of cyclohexanol ( $C_6H_1_0$ ). So, we can calculate the grams of cyclohexanol if we calculate the molar mass:

$(6*12)+(10*1)=82~g/mol$

With this value we can calculate the grams:

$10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0$

Now, we have as a product 500 mL of $C_6H_1_0$ . If we use the density value (0.811 g/mL). We can calculate the grams of product:

$500~mL\frac{0.811~g}{1~mL}=405.5~g$

Finally, with these values we can calculate the yield:

$%~=~\frac{405.5}{820}x100~=~49.45%$ %= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

6 0

3 years ago

Which of the following units would best measure the capacity of a baby bottle ?

Arisa [49]

I believe it would be A.Gram

~~~hope this helps~~~
~~davatar~~

7 0

4 years ago

An ice cube at 0.00 ∘C∘C with a mass of 21.5 gg is placed into 500.0 gg of water, initially at 31.0 ∘C∘C, in an insulated contai

4vir4ik [10]

Answer:

The temperature of the entire water sample after all of the ice has melted is 31.4 °C

Explanation:

This question relates to the first law of thermodynamics which states that energy can not be created nor destroyed but changes from one form to another

The specific heat capacity of water is 4.2 J/(g °C)

The latent heat of fusion of ice = 333.55 J/g

Mass of the ice = 21.5 g

Mass of the water = 500 g

Initial temperature of water = 31 °C

Therefore

Heat gained by the ice = 21.5 g × 333.55 J/g = 7162.725 J

= 500×4.2×(T-31)

Or T = 31.4 °C

Therefore the temperature of the entire water sample after all of the ice has melted is 31.4 °C

6 0

3 years ago