Answer:
The correct answer is B
Explanation:
Let's calculate the electric field using Gauss's law, which states that the electric field flow is equal to the charge faced by the dielectric permittivity
          Φ = ∫ E. dA =
 = ∫ E. dA =  / ε₀
 / ε₀
For this case we create a Gaussian surface that is a sphere.  We can see that the two of the sphere and the field lines from the spherical shell grant in the direction whereby the scalar product is reduced to the ordinary product
         ∫ E dA =  / ε₀
 / ε₀
The area of a sphere is
      A = 4π r²
    
     E 4π r² = / ε₀
 / ε₀
     E = (1 /4πε₀
)  q / r²
Having the solution of the problem let's analyze the points:
A   ) r = 3R / 4  = 0.75 R.
   In this case there is no charge inside the Gaussian surface therefore the electric field is zero
         E = 0
B) r = 5R / 4 = 1.25R
In this case the entire charge is inside the Gaussian surface, the field is
     E = (1 /4πε₀
)  Q / (1.25R)²
     E = (1 /4πε₀
)  Q / R2 1 / 1.56²
     E₀ = (1 /4π ε₀
)  Q / R²
     =  Eo /1.56
²
 =  Eo /1.56
²
    = 0.41 Eo
  = 0.41 Eo
C) r = 2R
All charge inside is inside the Gaussian surface
      =(1 /4π ε₀
) Q    1/(2R)²
 =(1 /4π ε₀
) Q    1/(2R)²
      = (1 /4π ε₀
) q/R²   1/4
 = (1 /4π ε₀
) q/R²   1/4
      = Eo  1/4
 = Eo  1/4
      = 0.25 Eo
 = 0.25 Eo
D) False the field changes with distance
The correct answer is B