Answer: Option (d) is the correct answer.
Explanation:
In winter's, temperature of atmosphere is low and due to this molecules of air present in the tire come closer to each other as they gain potential energy and loses kinetic energy.
Hence, air pressure decreases and there is need to fill more air in the tire.
Whereas is summer's, temperature is high so, molecules of air inside the tire gain kinetic energy and move rapidly from one place to another due to number of collisions. So, air pressure increases and there is no need to fill more air inside the tire.
Thus, we can conclude that the temperature is lower, so the air inside the tires contracts.
To solve this question you need to calculate the number of the gas molecule. The calculation would be:
PV=nRT
n=PV/RT
n= 1 atm * 40 L/ (0.082 L atm mol-1K-<span>1 * 298.15K)
</span>n= 1.636 moles
The volume at bottom of the lake would be:
PV=nRT
V= nRT/P
V= (1.636 mol * 277.15K* 0.082 L atm mol-1K-1 )/ 11 atm= <span>3.38 L</span>
Answer:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001 
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13 
From ideal gas equation P V = m RT
⇒ P = 
Put all the values in above formula we get
⇒ P = 
× 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
Answer:
a. True
b. True
c. False
d. True
Explanation:
a). A a very low substrate concentration , 
. Thus according to the Machaelis-Menten equation becomes
![$V_0 = \frac{V_{max} \times [S]}{Km}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%7D%24)
Here since the 
varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option (a) is true.
b). The Michaelis -Menten kinetics equation states that :
![$V_0 = \frac{V_{max} \times [S]}{Km+[S]}$](https://tex.z-dn.net/?f=%24V_0%20%3D%20%5Cfrac%7BV_%7Bmax%7D%20%5Ctimes%20%5BS%5D%7D%7BKm%2B%5BS%5D%7D%24)
Here the initial velocity changes directly with the substrate concentration as is directly proportional to [S]. But 
is same for any particular concentration of the enzymes. Thus, option (b) is true.
c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.
d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.
