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Fofino [41]
3 years ago
13

A sample of neon gas occupies 4.5 L of gas at 1.63 atm. What will be the volume if the pressure changes to 2.4 atm

Chemistry
2 answers:
NeTakaya3 years ago
6 0

Explanation:

<h3>BY USING BOYLE'S LAW , WE KNOW THAT </h3>

P1V1 = P2V2

P1=1.63atm \\ V1=4.5 L \\ P2=2.4 atm \\ V2=?

V2 =  \frac{1.63 \times 4.5}{2.4}

V2 = 3.05625 \: Litres

<h3>HOPE IT HELPS YOU</h3>

Alenkasestr [34]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 3.1 \ liters}}

Explanation:

This question asks us to find the new volume if the pressure changes. Therefore, we use Boyle's Law, which states that pressure and the volume of the gas are inversely proportional. The formula is:

P_1V_1=P_2V_2

We know that the original sample of gas occupies 4.5 liters at a pressure of 1.63 atmospheres.  We know that the pressure was changed to 2.4 atmospheres, but we don't know the volume. Substitute all known values into the formula.

4.5 \ L * 1.63 \ atm= 2.4 \ atm * V_2

Since we are solving for the new volume (V₂), we need to isolate the variable. It is being multiplied by 2.4 atmospheres and the inverse of multiplication is division. Divide both sides by 2.4 atm.

\frac {4.5 \ L * 1.63 \ atm}{2.4 \ atm}= \frac{2.4 \ atm * V_2}{2.4 \ atm}

\frac {4.5 \ L * 1.63 \ atm}{2.4 \ atm}= V_2

The units of atmospheres (atm) cancel.

\frac {4.5 \ L * 1.63 }{2.4 }=V_2

\frac {7.335 \ L}{2.4 }=V_2

3.05625 \ L= V_2

The smallest number of significant figures in the original measurements is 2, so our answer must have the same. For the number we found, that is the tenths place.

The 5 in the hundredth place tells us to round the 0 up to a 1.

3.1 \ L = V_2

The volume of the neon gas when the pressure is changed to 2.4 atmospheres is <u>3.1 Liters.</u>

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A 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, what
ludmilkaskok [199]

The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C

<h3>How to calculate temperature?</h3>

The initial temperature of the copper metal can be calculated using the following formula on calorimetry:

Q = mc∆T

mc∆T (water) = - mc∆T (metal)

Where;

  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

93.6T = 32342.4

T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

Learn more about temperature at: brainly.com/question/15267055

8 0
1 year ago
How many moles of hydrogen are required to react with 4.6 x 10 22 molecules of nitrogen?
V125BC [204]

Answer: 6 moles

Take a look at the balanced chemical equation for this synthesis reaction

N 2(g] + 3 H 2(g] → 2 NH 3(g]

Notice that you have a  1:3  mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have  2 moles of nitrogen taking part in the reaction, you will need

2 moles N 2 ⋅ 3 moles H 2 /1 mole N 2 = 6 moles H 2

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Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74
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Answer:

D

Explanation:

The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.

Q = mc∆T

Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)

∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)

From the data provided in the question, we can deduce that:

Q = 16.7KJ = 16,700J

m = 225g

c = 1.74J/g.k

For the temperature, let the final temperature be f. This means our ∆T = f - 20

16,700 = 225 * 1.74 * (f - 20)

16700 = 391.5 (f - 20)

f - 20 = 16700/391.5

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