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lions [1.4K]
1 year ago
8

You measure an angle of 21. 1 when the light passes through a grating with 610 lines per mm. what is the wavelength of the light

?
Physics
1 answer:
weqwewe [10]1 year ago
4 0

The wavelength of the light is 590nm

wavelength of the light=λ

Given,

The equation for a diffraction grating to use here is dsinθ = mλ

d=1/610 lines per mm=1.639*10^{-6}, m=1, θ=21.1^{0}

λ=1.639*10^{-6} * sin21.1^{0}/1 =590nm

<h3>Wavelength </h3>

The wavelength, which in physics refers to the length over which a periodic wave repeats, is its spatial period. It is the distance between two successive corresponding wave points of the same phase, such as two neighbouring crests, troughs, or zero crossings, and it is a feature of both travelling waves and standing waves, as well as other spatial wave patterns. The spatial frequency is defined as the wavelength's inverse. The Greek letter lambda, or "wavelength," is frequently used to represent it. Additionally, sinusoidal wave envelopes, modulated waves, and waves created by the interference of several sinusoids are also commonly referred to as having a wavelength.

You measure an angle of 21. 1 when the light passes through a grating with 610 lines per mm. what is the wavelength of the light?

Learn more about wavelength here:

brainly.com/question/13533093

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A train travels 65 kilometers in 5 hours, and then 61 kilometers in 4 hours. What is its average speed? _______km/hr
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The trains average speed is 13 km/hr.
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A current of 3.60A flows for 15.3s through a conductor. Calculate the number of electrons that pass through a point in the condu
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3.60 A = 3.60 coulombs of charge per second

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7 0
3 years ago
Last night Mookie Betts hit a baseball at 32.5 m/s at a 45° angle. Betts
podryga [215]

Answer:

a) Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.

b) The total distance traveled by the baseball was 108.7 m.

Explanation:

a) To know if the hit was a home run we need to calculate the height of the ball at 99 m:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final height =?

y_{0}: is the initial height = 1 m

v_{0_{y}: is the initial vertical velocity = v₀sin(45)

v₀: is the initial velocity = 32.5 m/s

g: is the gravity = 9.81 m/s²

t: is the time    

First, we need to find the time by using the following equation:

t = \frac{x}{v_{0_{x}}} = \frac{99 m}{32.5 m/s*cos(45)} = 4.31 s

Now, the height is:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} = 1m + 32.5 m/s*sin(45)*4.31 s - \frac{1}{2}9.81 m/s^{2}*(4.31 s)^{2} = 8.93 m      

Since the height of the baseball at 99 m was 8.93 m and the fence at that distance is 3m tall, the hit was a home run.

b) To find the distance traveled by the baseball first we need to find the time of flight:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

0 = 1 m + 32.5m/s*sin(45)t - \frac{1}{2}9.81 m/s^{2}t^{2}

1 m + 32.5m/s*sin(45)t - \frac{1}{2}9.81 m/s^{2}t^{2} = 0

By solving the above quadratic equation we have:

t = 4.73 s

Finally, with that time we can find the distance traveled by the baseball:

x = v_{0_{x}}*t = 32.5 m/s*cos(45)*4.73 s = 108.7 m

Hence, the total distance traveled by the baseball was 108.7 m.

I hope it helps you!                                                                                  

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Explanation:

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